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✓ 1 N 3 4 5 6 Conv A rectangular field is 300 meters long and 250 meters wide. What is the area of the field in square kilometer

garri49 [273]

Answer:

75 km

Step-by-step explanation:

Area = Length × Width

= 300m and 250m

= 75000m

M to Km => ÷1000

= 75000m ÷ 1000

= 75 km #

8 0

2 years ago

A pound of sand will spread over four square feet. How many pounds of sand would be needed to cover a sandbox that has a width o

Tju [1.3M]

20 pounds of sand will be required to cover a sandbox with a W of 8 and a L or 10.

To solve this question, first we calculate the area of the sandbox (A=LW)(8*10=80). If our sandbox requires 80 square feet of sand, then all we need to do is divide our area by the amount of square feet one pound of sand covers. (80/4=20). This means that it would require 20 pounds of sand to cover our 80 square foot sandbox.

4 0

3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

2 years ago

Is xy = yx? Explain how you know

blagie [28]

Answer:

Yes

Step-by-step explanation:

xy=yx because either way, you would end with the same product. For example, if x was 3 and y was 2, you would have (3)(2)=(2)(3), giving you 6=6 which is, in fact, a true statement.

4 0

2 years ago

Determine whether the relation is a function. (-3,3), (-2,2), (-1,1), (1,-1), (2,-2), (3,-3)

Luba_88 [7]

Answer:

Function

Step-by-step explanation:

Because there is an output for every input listed of its opposite.

3 0

2 years ago