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anastassius [24]

3 years ago

15

Can someone help me on this chart? the expressions for the perimeter of the rectangle is (4x2)+(2x2) =12

1 answer:

mars1129 [50]3 years ago

3 0

Answer:

hola que nesecitas yo no se ese deber

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Determine which of the following statements is true for the function<br> g(x) = 415 - 3x + 24- 1.

Zarrin [17]

Answer:

?

Step-by-step explanation:

what are the statements??

4 0

3 years ago

Hoochie [10]

Answer:

Google mid point formula and plug in your variables

Step-by-step explanation:

hope this helps :)

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4 years ago

Suppose that the probability density function ofthe length of computer cables is f (x) = 0.1 from 1200 to1210 millimeters.a. Det

Ann [662]

Notice that $f(x)=0.1$ for $1200\le x\le1210$ implies that $f(x)=0$ elsewhere, since

$\displaystyle\int_{1200}^{1210}f(x)\,\mathrm dx=1$

where $X=x$ is a random variable representing cable lengths according to the PDF $f(x)$ .

a. By definition of expectation, the mean is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f(x)\,\mathrm dx=0.1\int_{1200}^{1210}x\,\mathrm dx=1205$

The variance is

$\operatorname{Var}[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2$

where

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f(x)\,\mathrm dx=0.1\int_{1200}^{1210}x^2\,\mathrm dx=\frac{4,356,100}3$

so that the variance is $\frac{25}3$ , making the standard deviation $\frac5{\sqrt3}$ .

b. The proportion of cables within specs is

$P(1195$

8 0

4 years ago

A radioactive substance decays according to the formula

Leviafan [203]

Answer:

$t=4820 y$

Step-by-step explanation:

a) The half-life equation is given by:

$t_{1/2}=\frac{ln(2)}{k}$

b) Using the decay equation we have:

$Q(t)=15e^{-0.0001438t}$

we need to find t when $Q(t)=\frac{Q_{0}}{2}$

$7.5=15e^{-0.0001438t}$

$0.5=e^{-0.0001438t}$

$ln(0.5)=-0.0001438t$

$t=\frac{ln(0.5)}{-0.0001438}$

$t=4820 y$

Therefore, it will take 4820 years to decay to half the original amount.

I hope it helps you!

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3 years ago

Find the distance between the points (18,20) and (8,13)

ExtremeBDS [4]

2 and 5...................... hope I helped

7 0

4 years ago