All categories

2 years ago

Can someone help me on this chart? the expressions for the perimeter of the rectangle is (4x2)+(2x2) =12

Mathematics

1 answer:

mars1129 [50]2 years ago

3 0

Answer:

hola que nesecitas yo no se ese deber

You might be interested in

Elena needs to find a table that will fit three cube-shaped cases, each containing a frog.

iVinArrow [24]

The area of the table is 3.75 feet
The boxes are .83333 feet by .83333 feet so that area is .69
.69x3 is 2.07 so yes they will fit on top of the table

6 0

3 years ago

If the number of bacteria in a colony doubles every 210 minutes and the population is currently 8,000 bacteria, what will the po

Stells [14]

Answer:

D is the answer

64,000 exponential function

Step-by-step explanation:

64,000 exponential function

The number of bacteria in a colony doubles every 210 minutes.

The population of bacteria = 8000

Determine how many times the population will double.

$\frac{630}{210}$

= 3

Multiply the population by 2 a total of 3 times.

8000 × 2³ = 64,000

8 0

2 years ago

Homework help, no need to explain answer

Ainat [17]

Answer:

Square each side

Subtract 1 from each side

Divide by 3

Step-by-step explanation:

sqrt(3x+1) = 4

Square each side

(sqrt(3x+1))^2 = 4^2

3x+1 = 16

Subtract 1 from each side

3x+1-1 = 16-1

3x= 15

Divide by 3

3x/3 = 15/3

x = 5

8 0

3 years ago

the gas tank on a car holds 9.1 gallons. If the car goes 182 miles on a single tank, how many miles per gallon does the car get?

Nataly_w [17]

Just multiply 182 by the amount of gallons the car can hold<span />

6 0

3 years ago

Read 2 more answers

The number of typing errors made by a typist has a Poisson distribution with an average of seven errors per page. If more than s

Aleks [24]

Answer:

0.599 is the probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

We are given the following in the question:

The number of typing errors made by a typist has a Poisson distribution.

$\lambda =7$

The probability is given by:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that a randomly selected page does not need to be retyped

P(less than or equal to 7 mistakes in a page)

$P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599$

Thus, 0.599 is the probability that a randomly selected page does not need to be retyped.

4 0

3 years ago