Let the numbers be x and y. Then xy = -30 and x+y = -3.
Solve xy = -30 for y: y = -30/x
subst. -30/x for y in x+y= -3: x - 30/x = -3
Multiply all 3 terms by x: x^2 - 30 = -3x, so x^2 + 3x - 10 = 0
Solve this quadratic equation for x. x: {-5, 2}
If x = -5, then x+y = -3 becomes -5 + y = -3, and y = 2.
You should check to determine whether x=2 is also correct. If it is, what is the corresponding y value?
Step-by-step explanation:
Use the first fundamental theorem of calculus.
∫₆¹⁰ f'(x) dx = f(10) − f(6) = 8 − 8 = 0
Step-by-step explanation:
Discriminant : k² - 4(12)(27) < 0
So k² - 1296 < 0, -36 < k < 36.
Answer:
m=31/2, n=-24. (31/2, -24).
Step-by-step explanation:
2m+n=7
4m+3n=-10
-------------------
n=7-2m
4m+3(7-2m)=-10
4m+21-6m=-10
-2m=-10-21
-2m=-31
2m=31
m=31/2
2(31/2)+n=7
31+n=7
n=7-31
n=-24
Solution:
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