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BartSMP [9]
3 years ago
15

Mary baked a batch of three dozen cookies for 40 woman at the woman's club. Next month the woman's club is expecting 60 women to

attend the monthly meeting how many cookies should Mary bake?
Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

6 dozen

Step-by-step explanation:

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The sum of two numbers is 19 . When the second number is subtracted from the first​ number, the difference is 17 . Find the two
zhenek [66]

Answer:

19 and 2

Step-by-step explanation:

Let x represent the first number and y represents second number

x + y = 19

x - y = 17 add two equations up

2x = 36 divide both sides by 2

x = 19 and since the difference is 17 the other number is 2

4 0
2 years ago
What is the slope of the following equation?
777dan777 [17]

Answer: A. -3

Step-by-step explanation: The slope is the coefficent of x, this can be read as -3/1, down 3 over 1.

6 0
2 years ago
3 ice cream cones cost $8.25. At this rate , how much do 2 ice cream cones cost?
myrzilka [38]

Answer:

5.5

Step-by-step explanation:

8.25/3=2.75

2.75 times 2 is 5.5

4 0
2 years ago
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
Its #4 help please <br> question 4
sasho [114]

Answer:

I think s(2s) = 205

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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