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ExtremeBDS [4]
3 years ago
14

On a piece of paper, graph f(x)=16x0.5^x. Then determine which answer choice matches the graph you drew.

Mathematics
1 answer:
Reil [10]3 years ago
7 0

9514 1404 393

Answer:

  A

Step-by-step explanation:

You can use x=0 and x=1 to find points that must be on the graph.

  f(0) = 16·0.5^0 = 16

  f(1) = 16·0.5^1 = 8

Only graph A matches these points.

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A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
3 years ago
Someone helppppp plsss j suck at math. ( pls answer only if your sure ur right)
Degger [83]

Answer:

Step-by-step explanation:

4 0
3 years ago
The square root of 61 is in between 2 integers what are they
swat32
One way is to estimate
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
6^2=36
7^2=49
8^2=64
the number 61 is between 49 and 64 therefor the square root of 61is between the intigers 7 and 8 or -7 and -8
8 0
3 years ago
The formula to convert temperature in Celsius to Fahrenheit is F= 9/5C+32. Solve for C<br> C= ?
icang [17]
F = 9/5C + 32

Subtract 32 to both sides:

F - 32 = 9/5C

Divide 9/5 to both sides or multiply by its reciprocal, 5/9:

5/9(F - 32) = C

Simplify:

C = 5/9F - 160/9
6 0
3 years ago
Are the answers true or false
insens350 [35]

Answer:

T,F,T,F

Step-by-step explanation:

4 0
3 years ago
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