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kifflom [539]
3 years ago
9

See image thanks so much!!! it’s about dilations

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
Use x,y coordinate
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Julie and Eric row their boat (at a constant speed) downstream for 40 miles in 4 hours, helped by the current. Rowing at the sam
Liula [17]

Answer: 3 miles per hour

<u>Step-by-step explanation:</u>

Use the formula "distance (d) = rate (r) x time (t)" to create a system of equations.

Let "r" represent the rate they are rowing

Let "c" represent the current

                            time          rate      distance        <u>EQUATION</u>

Downstream:     4 hours     r + c       40 miles         4(r + c) = 40

Upstream:         10 hours    r - c        40 miles         10(r - c) = 40


Distribute, then eliminate r to solve for c:

Down: 4r + 4c = 40  →   5(4r + 4c = 40)  →   20r + 20c = 200

  Up: 10r - 10c = 40  → -2(10r - 10c = 40) → <u>-20r + 20c</u> =<u>  -80</u>

                                                                                40c = 120

                                                                              <u> ÷40  </u>  <u>÷40 </u>

                                                                                    c =   3

4 0
3 years ago
( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 =<br><br> Simplify the exponential expression
Korvikt [17]

Answer:

2

Step-by-step explanation:

\frac{(3*2)^4*3^{-3}}{2^3*3}

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4  * 2^4

\frac{3^4*2^4*3^{-3}}{2^3*3}

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1  are same

\frac{3^1*2^4}{2^3*3^1}

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2



4 0
3 years ago
Write a function for the situation discribed and find the value after 5 yrs. A $12,500 car depreciates 9% each year. Please help
sweet [91]
\bf \qquad \textit{Amount for Exponential Decay}\\\\&#10;A=P(1 - r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{initial amount}\to &12500\\&#10;r=rate\to 9\%\to \frac{9}{100}\to &0.09\\&#10;t=\textit{elapsed time}\\&#10;\end{cases}&#10;\\\\\\&#10;A=12500(1-0.09)^t\implies A=12500(0.91)^t&#10;\\\\\\&#10;\textit{after 5 years t = 5}\qquad A=12500(0.91)^5

and surely you know how much that is.
5 0
3 years ago
In this assignment, your team is managing a software development project with a total project budget of $178,500. Total work eff
gavmur [86]

Answer:

im lost good luck

Step-by-step explanation:

4 0
3 years ago
Sue has 18 sweets.
Rufina [12.5K]

Answer:

s = 13 - x

t = \frac{18+x}{2}

Step-by-step explanation:

To start out with:

s = 18

t = 18

Sue gives Tony x sweets

s = 18 - x

t = 18 + x

Sue then eats 5 of her sweets

s =  18 - x - 5 = 13 - x

t  = 18 + x

Tony eats half of his sweets

s = 13 - x

t = \frac{18+x}{2}

(Possible constraint that x\mod 2 = 0)

4 0
3 years ago
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