AC is diagonal of square ABCD, and the length of AC is 4. What is the area of the square?

1 answer:

8 0

Option d.
as we know the corner of a square is always 90°. So we can apply that (side of the square)^2+(side of the square)^2 = (diagonal of the side)^2

(side of the square)^2+(side of the square)^2 = 16
16/2=8
8=(side of the square)^2
side of square= squareroot of 8
area of square= squareroot of 8^2=8
hence answer is 8

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A three inch diameter pulley on an electric motor that runs at 1800

Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ. Then the tangential speed V is related to angular speed ω as:

$V=R\omega$

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

$\omega_1 R_1 = \omega_2 R_2\\$

$\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM$

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

$\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}$

$\omega_2 = 5654.7 \frac{radians}{min}$

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

3 0

3 years ago

If r=20.5 and s=34.2 find S Round to the nearest tenth

astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

$tan\alpha=\frac{opposite}{adjacent}$

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

$\alpha =arctan(\frac{opposite}{adjacent})$

Knowing that: you need to find the measure of the angle "S" , $r=20.5$ (which is the adjacent side) and $s=34.2$ (which is the opposite side), you can sustitute values into $\alpha =arctan(\frac{opposite}{adjacent})$