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Tcecarenko [31]
3 years ago
6

AC is diagonal of square ABCD, and the length of AC is 4. What is the area of the square?

Mathematics
1 answer:
dybincka [34]3 years ago
8 0
Option d.
as we know the corner of a square is always 90°. So we can apply that (side of the square)^2+(side of the square)^2 = (diagonal of the side)^2

(side of the square)^2+(side of the square)^2 = 16
16/2=8
8=(side of the square)^2
side of square= squareroot of 8
area of square= squareroot of 8^2=8
hence answer is 8

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Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,
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a_1=-10

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Step-by-step explanation:

we know that                              

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)                      

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a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5

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a_2-a_1=-7-(-10)=3              

a_3-a_2=-4-(-7)=3                  

a_4-a_3=-1-(-4)=3                        

a_5-a_4=2-(-1)=3                              

a_6-a_5=5-2=3                                                        

The difference between one term and the next is a constant        

This constant is the common difference                  

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The sequence graphed is an Arithmetic Sequence                    

therefore                                                                                    

The first term is a_1=-10                                    

The common difference is equal to d=3          

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