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Mademuasel [1]
2 years ago
9

Find the value of 2abcosC.

Mathematics
2 answers:
Strike441 [17]2 years ago
6 0

Answer:

7

Step-by-step explanation:

a=2

b=2

c=1

2ab cos C=a²+b²-c²=2²+2²-1²=4+4-1=7

Mazyrski [523]2 years ago
4 0

Answer:

C

Step-by-step explanation:

Given

a² + b² - 2abcosC = c² ( subtract c² from both sides )

a² + b² - c² - 2abcosC = 0 ( add 2abcosC to both sides )

a² + b² - c² = 2abcosC

Here a = 2, b = 2, c = 1 , then

2² + 2² - 1² = 2abcosC

4 + 4 - 1 = 2abcosC , then

2abcosC = 7 → C

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The distance between the two points is 13 units.

Step-by-step explanation:

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If x represents a number, write an expression in terms of x for seven less than three times this number divided
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Step-by-step explanation:

seven less than three times this number = 7 - 3x

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\frac{7 - 3x}{5 {x}^{2} }

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3 years ago
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find
Nonamiya [84]

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

<h3>How to find the Tension in Suspended Cables?</h3>

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

Read more about Tension in Cables at; brainly.com/question/11653585

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