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Mademuasel [1]
3 years ago
9

Find the value of 2abcosC.

Mathematics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

7

Step-by-step explanation:

a=2

b=2

c=1

2ab cos C=a²+b²-c²=2²+2²-1²=4+4-1=7

Mazyrski [523]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Given

a² + b² - 2abcosC = c² ( subtract c² from both sides )

a² + b² - c² - 2abcosC = 0 ( add 2abcosC to both sides )

a² + b² - c² = 2abcosC

Here a = 2, b = 2, c = 1 , then

2² + 2² - 1² = 2abcosC

4 + 4 - 1 = 2abcosC , then

2abcosC = 7 → C

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On Wednesday a local hamburgers shop sold a combined total of 568 hamburgers and cheeseburgers. The number of cheeseburgers sold
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four distinct circles are drawn in a plane. what is the maximum number of points where at least two of the circles intersect?
kolezko [41]

90 points where at least two of the circles intersect.

<h3>Define circle.</h3>

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.

Given,

Four distinct circles are drawn in a plane.

Start with two circles; they can only come together in two places. The third circle contacts each of the previous two circles in two spots each, bringing the total number of intersections up to four with the addition of a third circle. The total number of intersections will rise by another 6 when a fourth circle intersects the first three. And the list goes on.

As a result, we get a recognizable, regular pattern: for each additional circle, there are two more intersections overall than in the circle before it.

The total number of intersections can be expressed as the sum because the maximum number of intersections of 10 circles must occur when each circle contacts every other circle in 2 places each.

2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 = 90.

90 points where at least two of the circles intersect.

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3 0
1 year ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
3 years ago
I'm having trouble solving these two, any help?
mr_godi [17]

Answer:

32

Step-by-step explanation:

the number of options for doors (2) times the number of options for cylinder (2 )times the number of colour options (8) (2x2x8) is 32. My apologies I don't know about number 5

5 0
3 years ago
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