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3 years ago

What is the answer to this problem that I am having trouble with?

Mathematics

1 answer:

Gnesinka [82]3 years ago

4 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Read the values from the graph in the usual way: find the x-coordinate, then locate the point on the graph and find its y-coordinate.

You find the y-coordinate by following the horizontal line to the y-axis, where the numbers are.

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HELP ASAP (1O BRAILY/POINTS FOR ANSWER)

shutvik [7]

Step-by-step explanation:

x + y = 3 ---------------- eqn 1

y = -6x + 3 ------------- eqn 2

Substitute y for -6x + 3 in equation 1

x + -6x + 3 = 3

x - 6x + 3 = 3

-5x + 3 = 3

Collect like terms

-5x = 3 - 3

-5x = 0

Divide both sides by -5

x = 0

Hope this helped!

5 0

3 years ago

Read 2 more answers

I think its B can I get someone's opinion. Its not too hard. Plzzz Help.

shusha [124]

Answer:

I agree with you,I also think its B

Step-by-step explanation:

8 0

4 years ago

The figure below is an isosceles trapezoid. If m∠K=73, find the missing angle

beks73 [17]

Answer:

L 107°

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5 0

2 years ago

Toni simplified the expression , 22 × (16 −32 +1) ÷ 8. For Toni's first and second steps, he simplified the expression inside th

Anna007 [38]

When you subtract and add what is in the parentheses you would get -15 so I’m guessing he didn’t go from left to right when working inside the parentheses but when you solve the whole problem out you would get the answer: -41.25 If I missed something or you need me to show the work just let me know but I hope this helps !

6 0

3 years ago

Find the difference between points M(6,16) and Z(-1,14) to the nearest tenth.

svlad2 [7]

I'm not sure what you mean by difference, so I am guessing you meant to write "distance". If this is not the case, then feel free to report me. Anyway, to find the distance between two points you would use the distance formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Let's substitute our point coordinates into the formula. We'll substitute -1 and 6 for x_2 and x_1, and 14 and 16 for y_2 and y_1. After substituting, your formula will now look like: $d=\sqrt{(-1-6)^2+(14-16)^2}$ .