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2 years ago

HELP ASAP ASAP!! NO LINKS PLEASEEEE OR U WILL BE REPORTED, I NEED AN ANSWER, WILL GIVE BRAINIEST!!

Mathematics

1 answer:

Greeley [361]2 years ago

5 0

Answer:55555555

Step-by-step explanation: 555555555555

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The graph of y=tan(x) is vertically stretched by a factor of 7, shifted a distance of 12 units to the left, reflected across the

Mekhanik [1.2K]

Step-by-step explanation:

A transformation(s) of a parent function is

$f(x) = a(bx - c) + d$

where a is vertical compression/stretched or reflection

B is horinzotnal compression/stretch or reflection

C is horinzontal translation

D is vertical translation.

The parent function is

$y = \tan(x)$

First, we stretched this by 7

so we have

$y = 7 \tan(x)$

We need to shift this 12 units to the left so we have

$y = 7 \tan(x + 12)$

We need to reflect this across x axis so we get

$y = - 7 \tan(x + 12)$

We need to shift this downwards 15 so we get

$y = - 7 \tan(x + 12) - 15$

or because tan is a odd function you could say

$7 \tan( - (x + 12) ) - 15$

$7 \tan( - x - 12) - 15$

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2 years ago

What is the expanded form is 5.2684

jek_recluse [69]

The answer is 5+0.2+0.06+0.008+0.0004

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2 years ago

Find the explicit formula for -3,-33,-63,-93

bagirrra123 [75]

Answer:

a n = -3+(n-1)-30

Step-by-step explanation:

-3 - 30 = -33

-33 - 30 = -63

-63 - 30 = -93

The common difference here is -30. d = -30

The explicit formula is a n = a1 + (n-1)d

5 0

3 years ago

Use the fundamental counting principle to determine all the possible outcomes from rolling a die once then spinning the spinner.

Rudik [331]

The answer is there are 6 possible outcomes: {1, 2, 3, 4, 5, 6} Hope this helps!

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2 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

2 years ago