Answer:
a) f(x) translated up 4 units ⇒ vertical moving
b) f(x) stretched vertically by scale factor 5
c) f(x) translated 3 units to the left ⇒ horizontal moving
d) f(x) stretched horizontally by scale factor 1/0.1 = 10
e) f(x) compressed horizontally by scale factor 1/3 and reflected
about the y-axis
Step-by-step explanation:
∵ f(x) = 1/x
a) ∵ g(x) = 1/x + 4
∴ f(x) moved up 4 units ⇒ vertical moving
b) ∵ g(x) = 5(1/x)
∴ f(x) stretched vertically by scale factor 5
c) ∵ g(x) = 1/(x + 3)
∴ f(x) moved 3 units to the left ⇒ horizontal moving
d) ∵ g(x) = 1/0.1x
∴ f(x) stretched horizontally by scale factor 1/0.1 = 10
e) ∵ g(x) = 1/-3x
∴ f(x) compressed horizontally by scale factor 1/3 and reflected
about the y-axis
Area formula of a circle = πr2
π (8.5)2
Area= 226.98
Answer:
Step-by-step explanation:
(-2)^-3=
=
-
= -0.125
All the outcomes are 10 (possibilities)
To pull a quarter (total 3), its probability = 3/10 or 0.3
Now without putting the quarter back, the remaining total is now 9 (because one quarter was pulled out) so the probability of getting a penny is 2/9
But this is a conditional probability a) 1st pull a quarter & 2nd pull a penny
So the total probability is 3/10 x 2/9 =6/90 = 1/15 = 0.067
Answer: We are 95% confident that the mean income for all residents of this city is between $26700 and $35400.
Step-by-step explanation:
We know that a 95% confidence interval given an interval of values that we can be 95% sure , that it contains the true mean of the population, not 95% of data lies in it.
Given : A researcher is estimating the mean income of residents in a large city. The income variable is usually skewed to the right. She collects a random sample of 25 people.
The resulting 95% confidence interval is ($26700, $35400).
Then, valid conclusion will be : We are 95% confident that the mean income for all residents of this city is between $26700 and $35400.
