Remember that the vertex form of a parabola or quadratic equation is:
y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola (and a is half the acceleration of the of the function, but that is maybe too much :P)
In this case we are given that the vertex is (1,1) so we have:
y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:
-3=a(0-1)^2+1
-3=a+1
-4=a so our complete equation in vertex form is:
y=-4(x-1)^2+1
Now you wish to know where the x-intercepts are. x-intercepts are when the graph touches the x-axis, ie, when y=0 so
0=-4(x-1)^2+1 add 4(x-1)^2 to both sides
4(x-1)^2=1 divide both sides by 4
(x-1)^2=1/4 take the square root of both sides
x-1=±√(1/4) which is equal to
x-1=±1/2 add 1 to both sides
x=1±1/2
So x=0.5 and 1.5, thus the x-intercept points are:
(0.5, 0) and (1.5, 0) or if you like fractions:
(1/2, 0) and (3/2, 0) :P
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Answer:
C. 2y = (2x-1)/4
Step-by-step explanation:
An equation is linear when the exponents of the variables are 1 and the sum of the exponents of the variables in any term is 1.
a) 3xy = 4 . . . . sum of exponents is 1+1=2
b) f(x) = 2/3(1 -x^2) . . . . exponent is 2
c) 2y = (2x -1)/4 . . . . all exponents are 1 (linear)
d) y = 3/(x+1) ⇒ xy +y = 3 . . . . sum of exponents is 1+1 = 2
Second one is correct, that is an identity.
Third one is a contradiction:
6x - 15 = 3 * (2x - 6) ------> 6x - 15 = 6x - 18
Fourth one:
5x - 3 * (x - 4) = 2 * (x - 6) ---> 5x - 3x + 12 = 2x - 12 ---> 2x + 12 = 2x -12
So this is a contradiction as well.
Answer:
Part A
it supposed to be x⩾-1/3 since you divided by negative
Step-by-step explanation:
Part A
4-6x⩾-15x+1
step 1: add -6x to both sides
4-6x+6x⩾-15x+6x+1
=4⩾-9x+1
step 2: subtract 1 from both sides
4-1⩾-9x+1-1
3⩾-9x
step 3: do reflexive property and divide
3⩾-9x
= <u>-9x⩽3</u>
-9
x⩽-1/3
and since you divided by negative, the sign must change. so it'll be x⩾-1/3
