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Over [174]
3 years ago
13

WILL GIVE BRAINLIEST IF RIGHT!!

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

True

Step-by-step explanation:

Two angles form a pair of complementary angles

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HELPP AND SHOW YOUR WORK!!!
GarryVolchara [31]

Answer:

B) -10x+30

Step-by-step explanation:

You distribute:    

-10 times X minus 3 ( -10*x-3)

Which gives you:

Answer: -10x+30

Hope this helps!

3 0
3 years ago
A right triangle \mathrm{ABC}ABC is shown.<br><br> ​<br><br> ​ <br><br><br><br> What is cos AA?
maria [59]

Answer:

90

Step-by-step explanation:

6 0
3 years ago
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
Statement about 23 over six as a mixed number
pickupchik [31]
23/6
23 divided by 6 is 3 remainder 5 so it is 3 5/6

Hope this helps :)

8 0
3 years ago
I WILL GIVE CROWN PLS HELP NEED RIGHT ANSWER
FromTheMoon [43]

Answer:

Step-by-step explanation:

Surely you can figure out how many stairs she has to climb. She has to go down 4, back up to 0, and then up another 4, then back to 0

4 0
3 years ago
Read 2 more answers
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