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kati45 [8]
3 years ago
13

I’ll give you all my love and affection if you help me with this ASAP PLEASE ;)

Mathematics
1 answer:
guapka [62]3 years ago
4 0
Answer: (12,0)


Steps:

First, put the equation in slope-intercept form.

y=mx+b

1.5x + 4.5y =18

Subtract 1.5x from both sides.

4.5y =-1.5x +18

Divide both sides by 4.5 to isolate y.

y = -1/3x + 4


Then replace y with 0 because the point for the x-intercept is exactly on the x-axis so the y=0.

0 = -1/3x + 4

Subtract 4 from both sides

-4 = -1/3x

Divide both sides by -1/3 to isolate the x

12=x
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Andrew plans to retire in 32 years. He plans to invest part of his retirement funds in stocks, so he seeks out information on pa
Debora [2.8K]

Answer:

a) 0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

b) 0.4129 = 41.29% probability that the mean return will be less than 8%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean 8.7% and standard deviation 20.2%.

This means that \mu = 8.7, \sigma = 20.2

40 years:

This means that n = 40, s = \frac{20.2}{\sqrt{40}}

(a) What is the probability (assuming that the past pattern of variation continues) that the mean annual return on common stocks over the next 40 years will exceed 13%?

This is 1 subtracted by the pvalue of Z when X = 13. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{13 - 8.7}{\frac{20.2}{\sqrt{40}}}

Z = 1.35

Z = 1.35 has a pvalue of 0.9115

1 - 0.9115 = 0.0885

0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

(b) What is the probability that the mean return will be less than 8%?

This is the pvalue of Z when X = 8. So

Z = \frac{X - \mu}{s}

Z = \frac{8 - 8.7}{\frac{20.2}{\sqrt{40}}}

Z = -0.22

Z = -0.22 has a pvalue of 0.4129

0.4129 = 41.29% probability that the mean return will be less than 8%

8 0
2 years ago
the difference between two numbers is 10 and their sum is four times the smaller number. find the two numbers
Vanyuwa [196]

Answer:

The smaller number is 5.

The bigger number is 15.

Step-by-step explanation:

Let the smaller number be x and the bigger number be x+10.

x+x+10 = 4x

2x+10 = 4x

10 = 4x-2x

2x = 10

x = 10÷2

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x+10 = 5+10

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8 0
3 years ago
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14(4)÷(7)+5(17)-3 please help

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Read 2 more answers
Suppose that you are an elementary school teacher and you are evaluating the reading levels of your students. You find an indivi
aleksklad [387]

Answer:

The child's reading level is at the 3.4th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

You do some research and determine that the reading rates for their grade level are normally distributed with a mean of 90 words per minute and a standard deviation of 24 words per minute.

This means that \mu = 90, \sigma = 24

You find an individual that reads 46.4 word per minute. At what percentile is the child's reading level?

The percentile is the p-value of Z when X = 46.4, multiplied by 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.4 - 90}{24}

Z = -1.82

Z = -1.82 has a p-value of 0.034.

0.034*100 = 3.4

The child's reading level is at the 3.4th percentile.

6 0
3 years ago
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