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Drupady [299]
3 years ago
8

The image below is a triangle drawn inside a circle with center O: Which of the following expressions shows the area, in square

inches, of the circle? 3.14 •2 3.14 • 3 3.14 • 2² 2 • 3.14 • 2²

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0
We know that
[area of a circle ]=pi*r²
diameter=4 in
 r=4 in/2-----> 2 in

so
area=pi*2²-----> area of the circle=4*pi in²

the answer is
the area, in square inches, of the circle is <span>3.14 • 2²</span>
Veronika [31]3 years ago
5 0

Answer:

Option B is correct that is 3.14 . 2²

Step-by-step explanation:

We are given a figure of circle with center O.

From figure.

Length of the diameter of the circle = 4 inches.

⇒ Radius of the circle, r = 4 /2 = 2 inches.

Area of the circle is given by following formula,

Area\:of\:circle=\pi r^2

by putting value of π = 3.14 and radius, r = 2

we get,

Area\:of\:circle=3.14\times2^2

Therefore, Option B is correct that is 3.14 . 2²

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Factor y2 + 5y +6.<br> (y + 1)(y + 6)<br> (y + 2)(y + 3)<br> (y + 2)(y + 4)
Natali5045456 [20]

Factor y2 + 5y +6.

Multiply all of the multiple choices

(y+1)(y+6)

(y*y)(y*6)(+1*y)(+1)(+6)

y^2+6y+y+6

=y^2+7y+6

(y+2)(y+3)

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y^2+3y+2y+6

=y^2+5y+6

Answer: (y + 2)(y + 3)

5 0
3 years ago
What’s the answer to this question if your right I’ll keep giving you points
andreyandreev [35.5K]

\huge\text{$m\angle O=\boxed{11^{\circ}}$}

Since we know that all angles in a triangle add up to 180^{\circ}, we can solve for x and substitute it back into (x-5)^{\circ} to find m\angle O.

\begin{aligned}m\angle N+m\angle O+m\angle P&=180\\(5x-8)+(x-5)+(6x+1)&=180\end{aligned}

Remove the parentheses and combine like terms.

\begin{aligned}5x-8+x-5+6x+1&=180\\(5x+x+6x)+(-8-5+1)&=180\\12x-12&=180\end{aligned}

Add 12 to both sides of the equation.

\begin{aligned}12x-12&=180\\12x&=192\end{aligned}

Divide both sides of the equation by 12.

\begin{aligned}x=16\end{aligned}

Now that we have the value of x, we can substitute it back into (x-5)^{\circ} to find m\angle O.

\begin{aligned}m\angle O&=(x-5)\\&=16-5\\&=\boxed{11}\end{aligned}

7 0
3 years ago
A student wants to study the ages of women who apply for marriage licenses in his county. He selects a random sample of 94 marri
brilliants [131]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

For this case the confidence interval obtained is: (23.6 ; 27.3)

And the best interpretation would be:

We have 95% of confidence that the true mean os ages of women who apply for marriage licenses in his county is between 23.6 and 27.3

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

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Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

For this case the confidence interval obtained is: (23.6 ; 27.3)

And the best interpretation would be:

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