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3 years ago

What number should be added to both sides of the equation to complete the square?

Mathematics

1 answer:

baherus [9]3 years ago

4 0

-4 is what you put on both sides Bc it’s half of b

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(1.02)

AVprozaik [17]

Answer:

-14

Step-by-step explanation:

3r2-5s+6t

3.2.2-5(-4)+6.(-1)

12-20-6

12-26

-14

7 0

3 years ago

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the owner of an aquatic store used 17 1/2 gallons of water to fill aquariums. he puts 5 5/6 gallons of water in each aquarium. h

BabaBlast [244]

I have absolutely no idea. sorry that i didn’t answer but thanks for the second answer that i needed to ask my question. i’m stupid do i have no idea what it’s asking. sorry

6 0

3 years ago

Find an equation of the circle that satisfies the given conditions.

hodyreva [135]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}$

4 0

3 years ago

What is the value 0.36*11/2

Rashid [163]

1.98

hope this helps have a nice day and i would appreciate if you mark me brainlest

6 0

3 years ago

PLEASE HELP ME !!<br><br> i’ll mark brainliest if you’re correct

exis [7]

analyze problem

no need for distance formula

same x, only need to subtract y

3a-0=3a

8 0

2 years ago

Read 2 more answers