So we are given a system:
![3x-2y+3z=0\\ -3x - 5y - 5z= -21](https://tex.z-dn.net/?f=3x-2y%2B3z%3D0%5C%5C%0A-3x%20-%205y%20-%205z%3D%20-21)
Substitute x = 2 we get the system:
![-2y+3z=-6\\ - 5y - 5z= -15](https://tex.z-dn.net/?f=-2y%2B3z%3D-6%5C%5C%0A-%205y%20-%205z%3D%20-15)
Multiply the first equation by -5 and the second by 2 we get the system:
![10y-15z=30\\ - 10y - 10z= -30](https://tex.z-dn.net/?f=10y-15z%3D30%5C%5C%0A-%2010y%20-%2010z%3D%20-30)
Adding the two equations we get :
![-25z=0\text{ then}z=0.](https://tex.z-dn.net/?f=-25z%3D0%5Ctext%7B%20then%7Dz%3D0.)
We find the value of y by using any of the other equations like this:
![-2y=-6\\y=3.](https://tex.z-dn.net/?f=-2y%3D-6%5C%5Cy%3D3.)
Final solution:
B. looks like the way to go.
Answer: side
Step-by-step explanation:
Answer:
72.1 and -48.1
Step-by-step explanation:
I set up the equations x + y = 24 and x*y=-3468. Then I substituted for y and used the quadratic formula to come to two numbers rounded to about 72.1 and -48.1. Hope that helps :)
Pretty sure the answer is A