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3 years ago

Simplify the expression. 16m - 3/5 + 4m - 2 2/5 + 4

Mathematics

1 answer:

Oxana [17]3 years ago

8 0

Answer:

it is either B or C

Step-by-step explanation:

Combine Like Terms

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When two fractions are between 0 and 1/2, how do you know which fraction is greater? explain

Zina [86]

Example- 1/3 or 1/5, which is larger? If you divide 1 by 3 the answer is 0.33 If you divide 1 by 5 it's 0.2. Since 0.33(1/3) is larger that would be the answer.
<span>basically what you divide the top by the bottom to see which is larger. Then compare the fractions.</span>

3 0

4 years ago

Stephen Joyce’s charge account uses the unpaid-balance method and charges a monthly period rate of 1.9%. His finance charge was

dsp73

Let the unpaid balance amount be represented by = x

Rate of interest is = 1.9 %

Stephen paid an amount of = $21.77

This 21.77 is the amount of 1.9% of x

So, $\frac{1.9x}{100}=21.77$

$1.9x=2177$

x = 1145.789 or rounding it we get 1145.79

So, the unpaid balance of Stephen Joyce is $1145.79

8 0

3 years ago

What is the inverse of the 3 equations

stepan [7]

The multiplicative inverse of 3 is 1/3.

7 0

3 years ago

Read 2 more answers

Is (-3,4) a solution to y=2x+2??

iVinArrow [24]

Answer:

NO i do not think so because you would end with a -4 not positive because a positive times a negative is a negative so (-3,4) is not a solution.

I hope this helps sorry if am wrong

Step-by-step explanation:

7 0

3 years ago

In Major League Baseball, the American League (AL) allows a designated hitter (DH) to bat in place of the pitcher, but in the Na

hammer [34]

Answer:

Step-by-step explanation:

From the given information:

Let:

$\mu_1$ represent the population mean no. for DH group.

$\mu_2$ represent the population mean no. for no DH group

$n_1$ represent the sample sizes of DH

$n_2$ represent the sample sizes of no DH

Sample size: $n_1 = n_2 = 20$

For both groups, the population standard deviation of runs scored = 2.54

i.e

$\sigma^2_1 = \sigma_2^2 = 2.54$

The null & alternative hypothesis;

$H_o : \mu_1 \le \mu_2 \\ \\ H_a: \mu_1 > \mu_2$

Level of significance:

The test statistics is:

$z = \dfrac{\bar x_1 - \bar x_2}{\sqrt{\dfrac{\sigma^2_1}{n_1} + \dfrac{\sigma_2^2}{n_2} }}$

where;

$\bar x_1$ = sample mean for DH group

$\implies \dfrac{1}{n_1} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(0+6+8+2+2+4+7+7+6+5+1+1+5+4+4+5+7+11+10+0) \\ \\ = \dfrac{92}{20}$

= 4.6

$\bar x_2$ = sample mean for no DH group

$\implies \dfrac{1}{n_2} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(3+6+2+4+0+5+7+6+1+8+12+4+6+3+4+0+5+2+1+4) \\ \\ = \dfrac{83}{20}$

= 4.15

Now:

$z = \dfrac{4.60- 4.15}{\sqrt{\dfrac{2.54^2}{20} + \dfrac{2.54^2}{20} }} \\ \\ = \dfrac{0.45}{\sqrt{0.32258 +0.32258 }} \\ \\ = \dfrac{0.45}{0.803219} \\ \\$

= 0.5602

Since the test is one-tailed by looking at that $H_a:$

The P-value = $P(Z > z)$

$\implies 1 - P(Z \le z) \\ \\ = 1 - P(Z \le 0.5602)$

Using Excel Function " =normdist(z)"; we have":

$= 1- 0.7123$

P-value = 0.2877

Decision rule: To reject $H_o$ , if $p-value < \alpha \ at \ 0.10$

Conclusion: SInce P = 0.2877 which is $> \ \alpha \ at \ 0.10.$

We fail to reject the $H_o$ and conclude that there is insufficient evidence to support the given claim that: $\text{more runs are scored in games for which DH is used.}$

8 0

3 years ago