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Vikentia [17]
3 years ago
14

How much will jay investment be worth in eight years if she invested $13,500 at 5.2% in interest compounded semiannually

Mathematics
1 answer:
schepotkina [342]3 years ago
5 0

13,500 at 5.2 for 8 years compounded semi-annually.


Total = Principal * (1 + rate/n) ^n * years

where "n" = number of compounding periods per year.


Total = 13,500 * (1 + .052 / 2) ^ 2 * 8


Total = 13,500 * (1.026) ^ 16


Total = 13,500 * 1.5078487226


Total = 20,355.96


Source

1728.com/compint3.htm



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Part B) Semiannual \$66,862.38  

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Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

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t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

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