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Katarina [22]
3 years ago
15

6m squared minus 13m plus 6

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0
The expression is not factorable with rational numbers. This works if you’re doing The quadratic formula.
m
=
13
±
√
145
2
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A coin is tossed 5 times. Find the probability that none are heads. Find the probability that at most 2 are heads.
kiruha [24]
1- the answer is 1/32


each time we flip a coin the whole probabilities are 2
if we flip it 5 times
2*2*2*2*2=32

6 0
3 years ago
All of the following expressions are equivalent except.___ 2+m m+2 m-(-2) -2-m
Pachacha [2.7K]

Answer:

\Huge \boxed{-2-m}

Step-by-step explanation:

2 + m

Rewrite with variable first.

m + 2

m + 2

Can’t be simplified further.

m - (-2)

Distribute negative sign.

m + 2

-2-m

Rewrite with variable first.

-m - 2

The last expression is not equivalent to m+2.

4 0
3 years ago
Verify the property a x (b+c) =(a x b)+(a x c) by taking: a = -7, b = (2/5), c = (-3/7)
Margaret [11]
(-7)*(2/5 + (-3/7))
= -14/5 + 3
=1/5
5 0
3 years ago
Find the 6th term of a geometric sequence with t1=5 and r = -1/2
Hoochie [10]
In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,
   
                 An = (A₀)(r)ⁿ ⁻ ¹ 
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms. 

Substitute the known values to the equation,

                   An = (5)(-1/2)⁶ ⁻ ¹
                   An = -5/32

Hence, the answer to this item is the third choice, -5/32. 
5 0
3 years ago
Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)
Arlecino [84]
y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt

By the fundamental theorem of calculus,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}

Now the arc length over an arbitrary interval (a,b) is

\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx

But before we compute the integral, first we need to make sure the integrand exists over it. x^{3/2} is undefined if x, so we assume a\ge0 and for convenience that a. Then

\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)
6 0
3 years ago
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