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mr_godi [17]
3 years ago
9

HELP ASAP EASY 5x4^0

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0

Answer:

its 5

Step-by-step explanation:

you are multiplying 5 times 4 to the 0 power. According to pemdas you have to do the exponents. So 4 to the 0 power would be 1. Then you continue with the rest of the equation  so it would be 5 times 1

Harman [31]3 years ago
5 0

Answer:

5

Step-by-step explanation:

The answer is 5 because x^0 is always 1, and 5*1 is 5.

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Integers are _____ irrational numbers.<br> always<br> sometimes<br> never
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We are two numbers <br> Our median is 3 <br> Our minimum is 2, What numbers are we?
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Answer:

2,4

Step-by-step explanation:

median=3

minimum is 2

first no. is 2

second no. is 4

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Encyclopedia Britannica's list of 20 World Class Orchestras include the following from the United States: Boston Symphony Orches
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Given: 

<span>1. Boston Symphony Orchestra,
2. Cleveland Orchestra,
3. Chicago Symphony Orchestra,
4. Los Angeles Philharmonic,
5. New York Philharmonic,
6. Philadelphia Orchestra,
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The probability that it will include at least one group from the US:

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4 years ago
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PLEASE HELP!! I will give BRAINLIEST!! What is the range of possible sizes for side x?
Novay_Z [31]

Answer:

.5 < x < 16.5

Step-by-step explanation:

The smallest x  can be is greater than the difference of the other two sides

8.5 -8 = .5

The largest x can be the less than the sum of the two sides

8.5+8 = 16.5

.5 < x < 16.5

7 0
3 years ago
Ginny's piggybank contained $8.80 in quarters, dimes, and nickels. there were two more than five times as many nickels as quarte
SSSSS [86.1K]

Answer:

There are 13 quarters, 67 nickels, and 22 dimes.


Step-by-step explanation:

The value of a quarter is $0.25, the value of dime is $0.10, and the value of a nickel is $0.05. Let there be q quarters, n nickels, and d dimes.

Let's write equations from the statements given:


<u>"Ginny's piggybank contained $8.80 in quarters, dimes, and nickels.":</u>

0.25q+0.1d+0.05n=8.80

<u>"there were two more than five times as many nickels as quarters":</u>

5q+2=n

<u>"4 less than twice as many dimes as quarters":</u>

<u>2q-4=d</u>


Plugging in equation 2 and 3 into equation 1, we can solve for q:

0.25q+0.1(2q-4)+0.05(5q+2)=8.80\\0.25q+0.2q-0.4+0.25q+0.1=8.80\\0.7q=8.80+0.4-0.1\\0.7q=9.1\\q=\frac{9.1}{0.7}=13

<em>Substituting q = 13 into equation 2 will give us nickels:</em>

n=5q+2\\n=5(13)+2\\n=67

<em>Substituting q = 13 into equation 3 will give us dimes:</em>

d=2q-4\\d=2(13)-4\\d=22


There are 13 quarters, 67 nickels, and 22 dimes.

4 0
3 years ago
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