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3 years ago

I need help with 32 please help!!

Mathematics

1 answer:

ser-zykov [4K]3 years ago

5 0

Im not doing the answer but here is a super awesome way to figure it out with tens. and since you ave a computer just use calculator. if the exponent is over a ten, its literally telling u how many zeros to put so if I have 10^5 I put 5 zeros behind it. So just do that in a calculator to get the values and then its as simple as a 3rd grade question

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The shaded region in the graph represents the solutions of this system of linear inequalities:

kotegsom [21]

Answer:

$y$

$y\leq 2x+3$

Step-by-step explanation:

step 1

Find the equation of the solid line

From the graph take the points (0,3) and (4,11)

Find the slope

$m=(11-3)/(4-0)\\m=8/4=2$

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=2$

$b=3$ ----> the y-intercept is the point (0,3)

substitute

$y=2x+3$

therefore

The inequality is

$y\leq 2x+3$

step 2

Find the equation of the dashed line

The slope is given

$m=4$

From the graph take the y-intercept (0,-5)

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=4$

$b=-5$

substitute

$y=4x-5$

therefore

The inequality is

$y$

because the shaded region is below the dashed line

therefore

The system of inequalities is

$y$

$y\leq 2x+3$

8 0

3 years ago

An internet search has 220000 results. How does the value of 2 in the leftmost position compare to the value of other 2 in the n

Lilit [14]

Answer:

its 10x the value.

Step-by-step explanation:

20000 x 10 = 220000

5 0

3 years ago

In triangle ABC, angle = 90 degrees. AC = 7, BC = 12. AB = _______ Measure of angle A = _______ Measure of angle B = _______

Ulleksa [173]

Answer:

AB = 13.89

Measure of angle A = 59.74°

Measure of angle B = 30.26°

Step-by-step explanation:

The given parameters are;

∠C = 90°

AC = 7

BC = 12

Part 1

Hence, the question has the dimensions of the two adjacent sides of the right angle (angle 90°)

From Pythagoras theorem, we have;

A² = B² + C²

Where, A is the opposite side to the right angle, hence;

In the ΔABC,

AB ≡ A

Therefore;

AB² = AC² + BC² = 7² + 12² = 193

∴ AB = √193 = 13.89

Part 2

∠A is the side opposite side BC such that by trigonometric ratios

$tan \angle A = \frac{Opposite \, side \, to \, angle \, A}{Adjacent \, side \, to \, angle \, A} = \frac{BC}{AC} = \frac{12}{7} = 1.714$

∴ ∠A = Arctan(1.714) or tan⁻¹(1.714) = 59.74°

Part 3

∠B is found from knowing that the sum of the angles in a triangle = 180°

∴ ∠A + ∠B + ∠C = 180° which gives

59.74° + 90° + ∠B = 180°

Hence, ∠B = 180° - (59.74° + 90°) = 180° - 149.74° = 30.26°.

7 0

3 years ago

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Do number 20 please i need help

Sedaia [141]

The store's sales equate to $6000

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3 years ago

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Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911

nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

$\lambda=\dfrac{1}{2}$

(a) What is the expected number of 911 calls in one hour?

$\lambda=\dfrac{1}{2}\times 60=30$

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

$\lambda=\dfrac{1}{2}\times 5=2.5$

Number of calls = 3

So, P(X=3) is given by

$P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138$

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

$P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820$

Hence, a) 30, b) 0.2138, c) 0.0820

4 0

3 years ago