All categories

2 years ago

-1 1/2 5/6 + 3/14 / 3/7 + 3/2 1/2

Mathematics

1 answer:

Advocard [28]2 years ago

8 0

Answer:

-1 2/27

Step-by-step explanation:

-1 1/2 × 5/6 + 3/14 ÷ 3/7 + 3/2 × 1/2

= -1 1/4 + 3/14 ÷ 1 13/14 × 1/2

= - 1 1/28 ÷ 27/28

= -1 2/27

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By what percentages are Sweden's high category and medium category less than the United States' categories (to the nearest perce

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REQUIRED CHART :

The required chart has been attached

Answer:

31.8%

30.0%

Step-by-step explanation:

Required :

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2 years ago

Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is com

lora16 [44]

A)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twelve months, thus}
\end{array}\to &12\\
t=years\to &1
\end{cases}
\\\\\\
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b)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}$

c)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four quarters, thus}
\end{array}\to &4\\
t=years\to &1
\end{cases}
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3 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

-1 1/2 *5/6 + 3/14 / 3/7 + 3/2 * 1/2

-1 1/2 5/6 + 3/14 / 3/7 + 3/2 1/2