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kkurt [141]
3 years ago
5

Explain your answer so I can understand

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0
If all the sides equal(1.2mi and he’s riding on all sides) then he would have to ride his path 6.25 times because 30 divided by 4.8 is 6.25 if he’s only riding on one side then he would ride his path 25 times because 30 divided by 1.2 is 25
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Your first assignment at El Smello Perfume Co. is to determine the proper setting for filling the bottles. The company wishes to
SCORPION-xisa [38]

Answer:

The answer is "96.864 ml".

Step-by-step explanation:

In this question, the formula of \bold{CI = X \pm t \times s}.

( where X is the mean, t is the coefficient, and s is the mean difference error)

As a result, only 2.5% of containers might include less than 100 ml of volume, its trust coefficient could indeed be used in accordance with 95%, which is t=1.96.  

And it can take \pm \ 1.6 \ ml to have been the full value the standard infinite:  \to CI = 100 \pm (1.96 \times 1.6) \\\\

         = 100 \pm (3.136) \\\\

Consequently, if the standard error is  \pm \ 1.6 \ ml , a similar amount should be used to fill  

= 100 - 3.136 \\\\= 96.864 \ \ mL

5 0
3 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
Later, someone wants to use the data to find the amount of water at times before the sensor started. What should the sensor have
valkas [14]

it 4.56 that how i know because

6 0
3 years ago
Can someone help please thank you so much
Fofino [41]
1/2m-3/4(8)=16 m would be 44
8 0
2 years ago
Consider the arithmetic sequence:
prisoha [69]

Answer:

<em>Answer: D</em>

Step-by-step explanation:

<u>Arithmetic Sequences </u>

The arithmetic sequences are those where any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the arithmetic sequence:

10, 12, 14, 16, ...

Where a1=10 and

r = 12 - 10 = 2

Thus the general term is:

a_n=10+(n-1)2

Operating:

a_n=10+2n-2

a_n=8+2n

Answer: D

4 0
3 years ago
Read 2 more answers
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