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3 years ago

ZC is opposite B А A. B. AC C. C D. AB E. ZA FAC and BC

Mathematics

1 answer:

zmey [24]3 years ago

5 0

Answer:

Step-by-step explanation:

∠ C faces side AB, thus

∠ C is opposite AB → D

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choose all properties that were used to simplify the following problem: step 1 2/7 • 53 • 7/2 step 2 53 • 2/7 • 7/2step 3 53 • 1

den301095 [7]

Step 2: commutative property of multiplication
Step 3: multiplicative inverse
Step 4: multiplicative identity

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3 years ago

Read 2 more answers

The sale price of every item in a store is 75% of its usual price. A. The usual price of a jacket is $80, what is its sale price

riadik2000 [5.3K]

75 × 0.01 = 0.75

0.75 × 80 = $60

75 ×0.01 = 0.75

0.75 × 28 = $21

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3 years ago

X-2y=18 2x+y=6 parallel perpendicular or neither

sergey [27]

<h3>Therefore they are perpendicular.</h3>

Step-by-step explanation:

A equation of line is

y =mx +c

Here the slope of the line is m.

Given equations are

x - 2y = 18

⇔-2y = -x +18

$\Leftrightarrow y =\frac{1}{2} x -9$ ............(1)

and 2x + y = 6

⇔y = -2x +6 ............(2)

Therefore the slope of equation (1) is $(m_1)$ = $\frac{1}{2}$

Therefore the slope of equation (2) is $(m_2)$ = -2

If two lines are perpendicular, when we multiply their slope we get -1.

therefore,

$m_1. m_2$ = $\frac{1}{2}$ . (-2) = -1

Therefore they are perpendicular.

4 0

3 years ago

A lawn mowing service charges customers a flat fee plus an hourly rate for their services. The expression 55x + 15 is used to ca

EastWind [94]

Answer:

JK+7]BBUH ,.H,YT MKY,TFY7YKJKKKKKKKKKJKJKHNJ[KL-L;*

Step-by-step explanation:

JK ITS B

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3 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 +

timama [110]

Looks like your function is

$f(x)=\dfrac x{6x^2+1}$

Rewrite it as

$f(x)=\dfrac x{1-(-6x^2)}$

Recall that for $|x|$ , we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

If we replace $x$ with $-6x^2$ , we get

$f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}$

By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2$

Solving for $x$ gives the interval of convergence,

$|x|^2$

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

3 0

3 years ago