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Nadusha1986 [10]
3 years ago
8

Two vertical posts stand side by side. One post is 12 feet tall while the other is 19 feet tall. If a 27 foot wire is stretched

between the tops of the posts, how far apart are the posts?
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

26.1 feet

Step-by-step explanation:

This question is solved using Pythagoras theorem

Pythagoras Theorem =

c² = a² + b²

c = longest side = 27 feet

One post is 12 feet tall while the other is 19 feet tall.

The vertical side = a is calculated as

19 - 12 = 7 feet.

The third side = b = how far apart they are = ?

Therefore,

27² = 7² + b²

b² = 27² - 7²

b = √27² - 7²

b = √(680)

b = 26.076809621 feet

Approximately = 26.1 feet

Therefore, the distance between the posts = 26.1 feet

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Answer:

<h3><em>which is a better investment and by how much</em></h3>

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Step-by-step explanation:

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Answer:

I = $ 649.60

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 14%/100 = 0.14 per year,

then, solving our equation

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The simple interest accumulated

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I (interest) = $625.78

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First, convert R as a percent to r as a decimal

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r = 0.12 rate per year,

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A = P(1 + r/n)nt

A = 2,320.00(1 + 0.12/12)(12)(2)

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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VikaD [51]

Answer:

see explanation

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cos41° = \frac{adjacent}{hypotenuse} = \frac{VW}{VX} = \frac{7}{VX}

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