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2 years ago

Solve and upload your work: 2x2-3x=5

Mathematics

2 answers:

MAVERICK [17]2 years ago

8 0

follow me say a thanks mark me branliest

2*2-3x = 5

4-3x = 5

-3x = -1

x = 1/3

SCORPION-xisa [38]2 years ago

7 0

- 1/3 is the answer

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A number is taken away from 40 and the result is 45 What is the number?

hammer [34]

Answer:

-5

Step-by-step explanation:

Given that ,

A number is taken away from 40 and the result is 45 .

Let :-

The required number be x .

According to Question :-

$:\implies$ 40 - x = 45

$:\implies$ - x = 45 - 40

$:\implies$ - x = 5

$:\implies$ x = -5

<h3>Hence the required answer is -5 .</h3>

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2 years ago

SOLVE AND SHOW WORK PLEASE!!!

Marianna [84]

1st equation x - 7 < 14:

x < 14 + 7 (add 7 to both sides)
x < 21 (add 14 + 7 so it can equal 21)

2nd equation x + 13 > 21:

x > 21 - 13 (subtract 13 from both sides)
x > 8 (subtract 21 - 13 so it can equal 8)

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3 years ago

Please do It fast, I need it

jeka94

The reduction was 1/5.

Because you are given the reduced values, multiply the reduced value by the inverrse of the factor:

Inverse of 1/5 = 5

Height = 3 x5 = 15

Base = 5 x 5 = 25

The base is 25

6 0

2 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

2 years ago

The metal that is used to hold stained glass pieces together is called __________. a. cement c. paste b. framing d. leading

liubo4ka [24]

Answer:

Paste is the answer if I remember

7 0

3 years ago

Read 2 more answers