Solve and upload your work: 2x2-3x=5

Dairy cows at large commercial farms often receive

IrinaK [193]

Answer:

a) The 99% confidence interval for the true mean milk production is (26.35 kg/d, 29.65 kg/d).

b) They would need to use a confidence level of 94.52%.

Step-by-step explanation:

a)

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. So

$M = 2.575*\frac{2.25}{\sqrt{12}} = 1.65$

The lower end of the interval is the mean subtracted by M. So it is 28-1.65 = 26.35 kg/d

The upper end of the interval is the mean added to M. So it is 28 + 1.65 = 29.65 kg/d.

The 99% confidence interval for the true mean milk production is (26.35 kg/d, 29.65 kg/d).

(b) If the farms want the confidence interval to be no wider than 1.25 kg/d, what level of confidence would they need to use?

Now we want to find the value of z when M = 1.25. So:

$1.25 = z*\frac{2.25}{\sqrt{12}}$

$0.6495z = 1.25$

$z = 1.92$ , that has a pvalue of 0.9726.

So the confidence level should be 1 - 2*(1-0.9726) = 0.9452

They would need to use a confidence level of 94.52%.

3 0

3 years ago

Please help!!!! For the exponential function...

Anarel [89]

Answer: b.) 40

Given that:

f(x) = 5 × 2ˣ

To find f(3), simplify insert [x = 3] in the given equation:

f(3) = 5 × 2³

f(3) = 5 × 2 × 2 × 2

f(3) = 40

4 0

2 years ago

Trigonometry Problem, only solve if you know how and can tell me how to solve it.

Crazy boy [7]

The distances from the point the plane leaves the ground are given by the

trigonometric relationships of right triangle and Pythagoras theorem.

A) The minimum distance to the base of the tower is approximately 874.57 ft.

B) The minimum distance to the top of the tower is approximately 882.76 ft.

Reasons:

A) The angle with which the airplane climbs, θ = 11°

Height of the tower which the airplane flies, T = 120 foot

The clearance between the tower and the airplane, C = 50 feet

Required:

The minimum distance between the point where the plane leaves the ground and the base of the tower, $\displaystyle d_{min}}$

Solution:

Height at which the plane flies over the tower, h = T + C

Therefore, h = 120 ft. + 50 ft. = 170 ft.

At the point the plane leaves the ground, we have;

$\displaystyle tan(\theta) = \mathbf{\frac{h}{d_{min}}}$

Which gives;

$\displaystyle tan(11^{\circ}) = \frac{170 \, ft.}{d_{min}}$

$\displaystyle d_{min} = \mathbf{\frac{170 \, ft.}{tan(11^{\circ})}} \approx 874.57 ft.$

The minimum distance between the point where the plane leaves the ground and the base of the tower, $\displaystyle d_{min}}$ ≈ 874.57 ft.

B) The minimum distance between the point where the plane leaves the ground and the tower, R, is given by Pythagoras's theorem as follows;

R² = $\displaystyle \mathbf{d_{min}}}$ ² + T²

Which gives;

R = √(*874.57 ft.)² + (120 ft.²)) ≈ 882.76 ft.

The distance from the point where the airplane leaves the ground to the tower, R ≈ 882.76 ft.

Learn more about Pythagoras theorem here:

brainly.com/question/11256912

7 0

2 years ago

−4p+9=−5 Plzzzzzzz help

Hoochie [10]

Answer:

p = 3.5 or p = 7/2

Step-by-step explanation:

-4p+9= -5

or, -4p = - 14

or, p = -14/-4

or, p = 7/2 = 3.5

5 0

4 years ago

Read 2 more answers

Given: m∠AKB = 25°

dexar [7]

Answer:

V = 255.98189 pi

SA = 172.64114π

Step-by-step explanation:

The first thing to do is find the radius.

the measure of angle AKO = 1/2 the measure of angle AKB

m< AKO = 12.5 degrees

Now use trig to find AO (aka the radius)

tan(12.5) = AO/25

AO = 25* tan(12.5)

I'm leaving it like this to get a more accurate number

Now to find the volume

the volume of a cone is pir^2h/3

plugging everything in we get:

pi(25*tan(12.5))^2 * 25/3

which is about 255.98189 pi

Now for surface area

(this is the moment I realize symbols exist)

SA = πr(r+√h²+r²)

plugging everything in we have

π(25tan(12.5))((25tan(12.5)+√625+(25tan(12.5))^2)

I know it looks like a lot but that's mainly because I left the radius as 25tan(12.5)

The Surface Area is about 172.64114π

8 0

3 years ago