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SCORPION-xisa [38]
3 years ago
10

Which lines are perpendicular to the line y – 1 = One-third(x+2)

Mathematics
1 answer:
Valentin [98]3 years ago
4 0

Answer:

y-1=-3(x+2)

Step-by-step explanation:

The equation of the given line:

y-1=\frac{1}{3}(x+2)

This equation is in the form y-y_{1}=m(x-x_{1}).  Therefore, 1/3 is the slope.

To find a perpendicular line, take the opposite reciprocal of the slope (-1/old slope).  Therefore, the slope of the perpendicular line is -3.

The equation of the perpendicular line: y-1=-3(x+2)

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Answer:

H=-(t-3)^2+13

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

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Now, let 'h' be the vertical height and 't' be the time taken.

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Now, as per question:

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H=-a(t-3)^2+13

Now, taking a = 1. So, the formula that can be used is:

H=-(t-3)^2+13

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