Question

Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a catalyst in organic reactions. Calculate the number of moles of HCl in 62.85 mL of 0.453 M hydrochloric acid.

Answer 1

Answer: 0.0285 moles of HCl is present in given amount of solution.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

$0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles$

Hence, 0.0285 moles of HCl is present in given amount of solution.