Answer:
Alkyne
Explanation:
The homologous series for this compound is the Alkyne because of the presence of the triple bond present between the third and fourth carbon atoms as seen in the picture attached.
Answer:
0.88 g
Explanation:
Using ideal gas equation to calculate the moles of chlorine gas produced as:-
where,
P = pressure of the gas = 805 Torr
V = Volume of the gas = 235 mL = 0.235 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of chlorine gas = ?
Putting values in above equation, we get:
According to the reaction:-
1 mole of chlorine gas is produced when 1 mole of manganese dioxide undergoes reaction.
So,
0.01017 mole of chlorine gas is produced when 0.01017 mole of manganese dioxide undergoes reaction.
Moles of = 0.01017 moles
Molar mass of = 86.93685 g/mol
So,
Applying values, we get that:-
<u>0.88 g of should be added to excess HCl (aq) to obtain 235 mL of at 25 degrees C and 805 Torr.</u>
<u>Answer:</u>
3.67 moles
<u>Step-by-step explanation:</u>
We need to find out the number of moles present in 350 grams of a compound.
Molar mass of = 24.305
Molar mass of = 35.453
So, one mole of = 24.305 + (35.453 * 2) = 95.211g
1 Mole in 1 molecule of =
Therefore, number of moles in 350 grams of compound = 0.0105 * 350
= 3.67 moles
Answer:
Ability to be bent = Malleability
Identity = Physical Change
Electrical Current = Conductivity
Dissolve = Solubility
Color, Phase, or Hardness = Physical Property
Answer:
The answer to this is
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters
Explanation:
To solve this we first list out the variables thus
Density of the water = 1.00 g/mL =1000 kg/m³
density of mercury = 13.6 g/mL = 13600 kg/m³
Standard atmospheric pressure = 760 mmHg or 101.325 kilopascals
Therefore from the equation for denstity we have
Density = mass/volume
Pressure = Force/Area and for a column of water, pressure = Density × gravity×height
Therefore where standard atmospheric pressure = 760 mmHg we have for Standard tmospheric pressure= 13600 kg/m³ × 9.81 m/s² × 0.76 m = 101396.16 Pa
This value of pressure should be supported by the column of water as follows
Pressure = 101396.16 Pa = kg/m³×9.81 m/s² ×h
∴ = 10.336 meters
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters