Question

How would the expression x^3-3sqrt(3) be rewritten using difference of cubes?

Answer 1

The difference of two cubes is factored by
x^3-y^3=(x-y)(x^2+xy+y^2)

In this case it would be

C) 

Answer 2

Answer:

Correct option is:

C. $(x-\sqrt{3})(x^2+3+x\sqrt{3} )$

Step-by-step explanation:

x^3-3sqrt(3)

=  $x^3-3\sqrt{3} \\\\=x^3-\sqrt{3}^3$

= $(x-\sqrt{3})(x^2+3+x\sqrt{3} )$

(since, $a^3-b^3=(a-b)(a^2+b^2+ab)$)

Hence, the correct option is:

   C.    $(x-\sqrt{3})(x^2+3+x\sqrt{3} )$