answer is B) Corresponding angles
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Answer:
Step-by-step explanation:
The total number of students (32) corresponds to the total number of ratio units (3+5 = 8), so each ratio unit represents 32/8 = 4 students.
The 3 ratio units representing boys will stand for 3×4 = 12 boys.
The 5 ratio units representing girls will stand for 5×4 = 20 girls.
There are 12 boys and 20 girls in Janice's classroom.
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<em>Additional comment</em>
I find the above solution to be the easiest.
You can also write a system of equations. Let b and g represent the numbers of boys and girls, respectively.
b/g = 3/5
b +g = 32
Multiplying the first equation by g gives an expression for b that can be substituted into the second equation:
b = (3/5)g
(3/5)g +g = 32
8/5g = 32 . . . . . . . . . . . . . . . . . collect terms
g = (5/8)(32) = 5·4 = 20 . . . . . . multiply by 5/8
b = (3/5)(20) = 3·4 = 12 . . . . . . . find b using the value of g
It landed on red 102 times out of 300 spins
that is 102/300 which can reduce to 17/50 as a fraction
17/50 = 0.34 as a decimal
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.
Multiply both sides by 100.
Divide both sides by 50.
The amount invested at 7% is 
.
The amount invested at 8% is
The amount invested at 9% is
Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
f(x+1) = -3/4 × f(x)
Step-by-step explanation:
first of all, the sign of the numbers in the sequence is alternating. so, there must be a "-" involved.
that eliminates the first and third answer options.
and the absolute values of the numbers in the sequence are going down. |f(x+1)| < |f(x)|
that eliminates the fourth answer option, as this says that
|f(x)| < |f(x+1)|. and that is the opposite of how the actual sequence behaves.
