Answer:
The amount of work required to raise the TV from point A to point B is equal to the amount of gravitational potential energy the TV gains from its height above the ground. This is generally true for any object ...
The hydrogen bonds that form between water molecules account for some of the essential and unique properties of water. The attraction created by hydrogen bonds keepswater liquid over a wider range of temperature than is found for any other molecule its size.
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<h2>Answer with Explanation</h2>
The symbol for the element is used to represent the valence electrons of an atom on the outer shell and they are shown as dots. These symbols help visualize whether the atoms and molecules exist as lone pairs or within bonds as the atoms either gains or loses or shares electrons in their valence level in order to achieve stability or complete its valence shell. These symbols are known as Lewis symbols that only show the electrons on the outermost shell as dots.
Kg=24,590550 g=24590,550 mg=24590550
Answer:
C₈H₈O₃
Explanation:
The empirical formula is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of C:H:O.
Assume 100 g of the compound.
1. Calculate the mass of each element.
Then we have 63.15 g C, 5.30 g H, and 31.55 g O.
2. Calculate the moles of each element
![\text{Moles of C} = \text{63.15 g C} \times \dfrac{\text{1 mol C}}{\text{12.01 g C}} = \text{5.258 mol C}\\\\\text{Moles of H} = \text{5.30 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H }} = \text{5.258 mol H}\\\\\text{Moles of O} = \text{31.55 g O} \times \dfrac{\text{1 mol O}}{\text{16.00 g O }} = \text{1.972 mol O}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20C%7D%20%3D%20%5Ctext%7B63.15%20g%20C%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20C%7D%7D%7B%5Ctext%7B12.01%20g%20C%7D%7D%20%3D%20%5Ctext%7B5.258%20mol%20C%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%20H%7D%20%3D%20%5Ctext%7B5.30%20g%20H%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20H%7D%7D%7B%5Ctext%7B1.008%20g%20H%20%7D%7D%20%3D%20%5Ctext%7B5.258%20mol%20H%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%20O%7D%20%3D%20%5Ctext%7B31.55%20g%20O%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20O%7D%7D%7B%5Ctext%7B16.00%20g%20O%20%7D%7D%20%3D%20%5Ctext%7B1.972%20mol%20O%7D)
3. Calculate the molar ratio of the elements
Divide each number by the smallest number of moles
C:H:O = 5.258:5.258:1.972 = 2.667:2.666:1
4. Multiply by a number to make each ratio close to an integer
Multiply the ratios by three.
2.667:2.666:1 = 8.000:8.000:3 ≈ 8:8:3
5. Write the empirical formula
EF = C₈H₈O₃