Decimal Form: 0.45
Fraction Form: 45/100 or 9/20
Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion: 
Significance level : 
Critical z-value :
(using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

i.e. 
i.e. 
i.e. 
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)
Answer:
1. 1458
2. 500 or -500
Step-by-step explanation:
1. a4=54, a5=162
r = 162/54 = 3
a7 = a5 × r²
= 162 × 3² = 1458
2.a4=-4, a6=-100
r² = -100/-4 = 25
r = +/- 5
a7 = a6 × r
= -100 × +/- 5
= +/- 500
Answer:
C
Step-by-step explanation:
A, B are wrong since 8,795 is a constant, it doesn’t change;
D is wrong since it is the starting cost, not total cost
The answer is (150,1) (2,112.5) and the last is (3,84) that’s the answer