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mr Goodwill [35]
3 years ago
13

Which situation demonstrates the law of large numbers ?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

The law of large numbers in probability, is a theorem that describes the result of performing the same experiment a large number of times because the average of the results obtained from a large number of trials is close enough to the expected value.

So, according to this definition and the situation given , the correct answer is option B - if 800 people are randomly surveyed about the TV shows they watch, about 400 of them will be women; because there are larger number of experiment.

Part B:

To get the expected value of a t-shirt we will multiply each of the 3 prices by the associated probability, and then add up these three products-

(24\times\frac{1}{6})+(30\times\frac{1}{2})+(36\times\frac{1}{3})

=4 + 15 + 12 = $31

Hence, option C is correct.

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A farm is to be built in the shape of Quadrilateral ABCD, as shown below. All four sides are equal.
lapo4ka [179]

9514 1404 393

Answer:

  65.52 square feet

Step-by-step explanation:

The area of a rhombus is half the product of the diagonals.

  A = (1/2)ab

  A = (1/2)(12.6 ft)(10.4 ft) = 65.52 ft²

The area of the farm is 65.52 square feet.

6 0
2 years ago
How do u solve this problem “15 = 2 − 5?”
aev [14]

Answer:

-3 is the answer

7 0
3 years ago
Read 2 more answers
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
Can someone finish the whole thing ??
Romashka-Z-Leto [24]
<h3>Answer:    y = (3/2)x + 0</h3>

This is the same as  y = (3/2)x

=============================================================

Work Shown:

Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - (-3))/(2 - (-2))

m = (3 + 3)/(2 + 2)

m = 6/4

m = 3/2

The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.

----------

Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-3) = (3/2)(x - (-2))

y + 3 = (3/2)(x + 2)

y + 3 = (3/2)x + (3/2)(2)

y + 3 = (3/2)*x + 3

y + 3 - 3 = (3/2)*x + 3 - 3

y = (3/2)x + 0

The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.

3 0
3 years ago
Help!
Sergeu [11.5K]

Incomplete question.  

7 0
2 years ago
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