A Book has 1257 digits in it page numbers. How many pages does the book have?

1 answer:

6 0

Each page from 10 to 99, inclusive (so total of 90 pages) needs two digits (for example page 12 needs two digits: 1 and 2); Each page from 100 to 200, inclusive (so total of 101 pages) needs three digits (for example page 123 needs three digits: 1, 2 and 3)

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Find the volume of the composite solid shown below, Round answer to the nearest hundredth.

MrMuchimi

First you’d start off by finding the volume of the rectangular prism on the bottom. The formula for this is lwh or (length*width*height) so you’d plug in the numbers and get 4*4*5 which multiplies out to be 80inches cubed. Next you’d have to find the volume of the pyramid by using the formula lwh/3 or ((length*width*height)/3) so it would be ((4*4*6)/3) and that equals 32inches cubed. Finally, you add the 2 volumes together so 80inches cubed+32inches cubed and get 112inches cubed. Hope this helps

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2 years ago

Which point is not on the graph of y =2x + 3?

Nostrana [21]

Answer:

i'm pretty sure its D

Step-by-step explanation:

if you make a graph yourself you'll see all the rel;relationship match except for d

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3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

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