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3 years ago

URGENT URGENT URGENT Find the value of x.

Mathematics

1 answer:

Alja [10]3 years ago

4 0

Answer:

x = 5.

Step-by-step explanation:

x is the radius of the circle.

The line of length 4 bisects the chord of length 6 into 2 line segments of length 3.

If we draw a line from the centre to where the chord of length 6 meets the circle we have another radius.

This is also the hypotenuse (h) of a right triangle, so we have a right triangle whose legs are 3 and 4, then:

h^2 = 4^2 + 3^2 = 25

h = 5

x = 5 (as x and h are both radii).

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5 decenas de millón, 8 centenas de millar

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Answer:

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Step-by-step explanation:

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2 years ago

Suppose that 65% of all registered voters in a certain area favor a waiting period before the purchase of a handgun. Among 225 r

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Answer:

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225 x 0.65 = 135

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2 years ago

One positive number is three more than twice another. If their product is 629, find the numbers.

sineoko [7]

Answer:

x = 17 and y = 37

Step-by-step explanation:

Let the numbers be x and y.

y = 3 + 2x

xy = 629

substituting y in the second equation we get

x(3+2x) = 629

3x + 2 $x^{2}$ = 629

2 $x^{2}$ + 3x - 629 = 0

Solving a quadratic equation by using its formula:

x = [-3 ±√(9-4(2)(-629)] / 4

x = [-3 ± √5041] / 4

x = [-3 ± 71] / 4

x = 17 and $\frac{-37}{2}$

Ignore the negative number in x and just use x = 17 in the first equation we get

y = 3 + 2(17) = 37

5 0

3 years ago

Find the imaginary solutions to the following quadratic function:

Temka [501]

Answer:

the solutions are these

Step-by-step explanation:

$\frac{3}{14} + \frac{ \sqrt{159} }{14} i \: and \\ \: \frac{3}{14} - \frac{ \sqrt{159} }{14} i$

8 0

3 years ago

Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B

Galina-37 [17]

Answer:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

8 0

3 years ago