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attashe74 [19]
3 years ago
13

Mount Everest is 8,850m tall. Convert the height to kilometers.

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0

Answer: 8.85km

Step-by-step explanation:

8,850m = 8,850 m⋅1 km / 1,000 m

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A set of wrist watch prices are normally distributed with a mean of 767676 dollars and a standard deviation of 101010 dollars. W
Akimi4 [234]

Answer:

0.8224

Step-by-step explanation:

Data

  • mean: $76
  • standard deviation, sd: $10
  • first value of interest, x1: $63
  • second value of interest, x2: $90

z-score for x1:

z1 = (x1 - mean)/sd = (63 - 76)/10 = -1.3

z-score for x2:

z2 = (x2 - mean)/sd = (90 - 76)/10 =  1.4

The  proportion of wrist watch prices are between $63 and $90 is:

P(z1 < z < z2) = P(z < 1.4) - P(z < -1.3)

P(z < 1.4) = 0.9192 (see first picture attached)

P(z < -1.3) = 0.0968 (see second picture attached)

P(z1 < z < z2) = 0.9192 - 0.0968 = 0.8224

7 0
3 years ago
A turtle crawled at a speed of 1.2 meters per minute for 9 minutes. How far did the turtle crawl? 7.5 meters 7.8 meters 10.2 met
Dennis_Churaev [7]

Answer:

10.8 meters

Step-by-step explanation:

3 0
3 years ago
Original price of an apple watch: $299.00 Sales Tax: 7%​
bixtya [17]

20.93 is 7% of that

7 0
3 years ago
Write an equation in point slope form for the line with a slope of 3 passes through (1,2)
alexgriva [62]

Answer:

y-2=3(x-1)

Step-by-step explanation:

The point-slope form of a line is given as:

y-y_1=m(x-x_1)

Where

m is the slope

x_1 is the x-coordinate of the point given (passing through the line)

y_1 is the y-coordinate of the point given (passing through the line)

Now,

Given,

Slope = m = 3

x_1 = 1

y_1 = 2

Now, we simply plug these into the formula for point-slope form of a line:

y-y_1=m(x-x_1)\\y-2=3(x-1)

This is the point-slope form.

4 0
3 years ago
Solve the following system of equations. What is one x-value of a solution?
gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

x = \frac{-36 \pm 33.11}{2}

x_1 = \frac{-36 + 33.11}{2}

x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

x_2 = -34.555

5 0
3 years ago
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