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Hoochie [10]
3 years ago
14

Simply the expression: 3^-8 X 3^4

Mathematics
1 answer:
Olin [163]3 years ago
7 0

Answer:

Exact Form:

1

81

Decimal Form:

0.01234567

…

Step-by-step explanation:

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A gardener wants to compare the heights of plants in two gardens that are watered using different tools. The heights, in centime
ryzh [129]

Garden A: 24.05cm ( add all the numbers(=457)and divide by the amount of numbers (19))

Garden B: 22.85cm ( add all numbers (=480) divide by amount of numbers (21))

3 0
3 years ago
The correct equation that goes through the point (3, 4) and is parallel to the line y=2x+1
abruzzese [7]

Answer: y = 2x -2

Step-by-step explanation: parallel is same slope diff y intercept

y = 2x

4 = 2(3) + x

4 = 6 + x

x = -2

6 0
3 years ago
If x^y = z is there any way to find y if you know x and z?
Rzqust [24]

We make use of y = \log_x(z) to solve for y, when you know x and z

<h3>How to solve for y?</h3>

The expression is given as:

x^y = z

The above expression is an exponential expression.

Start by taking the logarithm of both sides

y log(x) = log(z)

Divide both sides by log(x)

y = \log_x(z)

Hence, we make use of y = \log_x(z) to solve for y, when you know x and z

Read more about exponential functions at:

brainly.com/question/11464095

#SPJ1

6 0
2 years ago
The price of a book rises from £16 to £20 work out the percentage increase​
Vladimir79 [104]

Answer:

25%

Step-by-step explanation:

20-16=4

So

16…4

1 … 4/16

100…4/16×100

1/4×100

25%

5 0
3 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
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