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mihalych1998 [28]
3 years ago
13

ANYONE PLS HELPpppppppp!!

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0
Label the x-axis “Solo Practice Time (min)” and the y-axis “Number of baskets”.

label the graph as going up by 5s

Next, graph the points on the graph
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9 batteries cost 13 dollars.It's ratios and Rates
8090 [49]
One battery costs $1.44.

The unit rate would be
\frac{1.44}{1 battery}

To get that answer, you would have to divide 13 ÷ 9.

I'm not sure if this is what you were looking for, but if it was, I hope I helped! :-)
4 0
3 years ago
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PLEASE HELP ASAPPPPPPPPPPP
mixas84 [53]

\boxed{\boxed{\sf Area\:of\:the\:figure=10x^4-50x^3+5x^2+246x-196}}

Refer to the attachment for calculations.

6 0
3 years ago
Simplify the expression (2j+1)(2)
stiks02 [169]

Answer:

4j + 2

Step-by-step explanation:

Distribute:  

(2j * 2) + (1 * 2)

4j + 2

6 0
3 years ago
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A given population proportion is .25. What is the probability of getting each of the following sample proportions
anyanavicka [17]

This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 33 ) = √( 0.1875 / 33 ) = 0.0754

Now, P( p^ > 0.24 )  

= P[ (( p^ - μ ) /S.D) > (( 0.24 - μ ) / S.D)

= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754  ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 )  = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

6 0
2 years ago
0.6 as a fraction and percent
Ludmilka [50]
6/10 is the fraction and 60 percent
6 0
3 years ago
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