<span>A ball is thrown at a 30 degree angle above the horizontal with a speed of 10 ft/s. After 0.50s the horizontal component of it's velocity will be the same. In a projectile motion the horizontal component of the velocity is said to be constant. Therefore, it will be equal to the initial velocity.</span>
Answer:
Step-by-step explanation:
5
Answer:
20
Step-by-step explanation:
Total no = 75
N (P) = 48 , N (H) = 45 , N (T) = 58
N (P∩H) = 28 , N (H∩T) = 37 , N (P∩T) = 40
N (P∩H∩T) = 25
Total no = N (P) + N (H) + N (T) - N (P∩H) - N (H∩T) - N (P∩T) + N (P∩H∩T) + neither
75 = 48 + 45 + 58 - 28 - 37 - 40 + 25 + neither
75 = 71 + neither → neither = 4
N (only P) = N (P) - N (P∩H) - N (P∩T) + N (P∩H∩T) = 48 - 28 - 40 + 25 = 5
N (only H) = N (H) - N (P∩H) - N (H∩T) + N (P∩H∩T) = 45 - 28 - 37 + 25 = 5
N (only T) = N (T) - N (H∩T) - N (P∩T) + N (P∩H∩T) = 58 - 37 - 40 + 25 = 6
So, total liking either one or neither = 4 + 5 + 5 + 6 = 20
Answer:
For 5/11 shade in the third bubble (0.45 repeating)
