Whats 9+10<br> Im willing to give 25 Points. And dont say 19 CAUSE IT AINT THE ANSWER. LOL

A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide. A circle h

LuckyWell [14K]

The circumference of the outer edge of the path around the pool is 113.04 ft.

<h3>What is the circumference?</h3>

The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.

Given

A circular swimming pool has a radius of 15 ft.

There is a path all the way around that pool that is three feet wide.

A circle has a radius of 15 feet.

A larger circle goes around the smaller circle that is 3 feet wide.

The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.

The radius of the outer edge of the path around the pool = 15 + 3

The radius of the outer edge of the path around the pool = 18ft

The circumference of the outer edge of the path around the pool is;

$\rm Circumference=2\pi r\\\\Circumference = 2\times 3.14 \times 18\\\\Circumference=113.04 \ ft$

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.

To know more about circumference click the link given below.

brainly.com/question/5023328

8 0

2 years ago

In the function f(x)=6x^2-4, what is the value of f(-2)?

BartSMP [9]

In order to find the value of f(-2), you can plug -2 wherever x is.

f(x) = 6x^2 - 4

f(-2) = 6(-2)^2 - 4

f(-2) = 6(4) - 4

f(-2) = 24 - 4

f(-2) = 20

Thus, the value of f(-2) is 20. Hope this helps! If you have any other questions related to this, let me know.

4 0

3 years ago

Sam bought 8 pounds of rice for $5 . How many pounds of rice did he get per dollar? round to nearest hundredth

Natali [406]

well, i believe the answer is each dollar= 1.6 pounds

7 0

3 years ago

1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat

brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

$x = 2$ is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) $f(x) = 6x + 6/x$

$f\prime(x) = 6 - 6/x^2 = 0$ and $x \neq 0$

So, the roots are $x = -1$ and $x = 1$

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum.

2) $f(x)=6-4/x+2/x^2$

$f\prime(x)=4/x^2-4/x^3=0$ and $x \neq 0$

So the root is $x = 1$

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum.

3) $f(x) = 8x^2/(x-4)$

$f\prime(x) = (8x^2-64x)/(x-4)^2=0$ and $x \neq 4$

So the roots are $x = 0$ and $x = 8$

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum.

4) $f(x)=6(x-2)^{2/3} +4=0$

$f\prime(x) = 4/(x-2)^{1/3}$ has no solution and $x = 2$ is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

$x = 2$ is absolute minimum.

5) $f(x)=8\sqrt x - 6x$ for $x>0$

$f\prime(x) = (4/\sqrt x)-6 = 0$

So the root is $x = 4/9$

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum.

5 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago

Whats 9+10 Im willing to give 25 Points. And dont say 19 CAUSE IT AINT THE ANSWER. LOL