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irina [24]
3 years ago
13

35 POINTS

Mathematics
2 answers:
Artemon [7]3 years ago
5 0

Answer:

<em>there are parrele</em>

Step-by-step explanation:

dmitriy555 [2]3 years ago
3 0
If the lines are parallel, they have no solutions because they never touch
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Suppose x represents an objects weight on Earth. Write two expressions: one that you can use to find the objects weight on Mars
tatyana61 [14]
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
4 0
3 years ago
PLZ HELP ASAP SOLID GEOMETRY
eduard
It should be E) none of the above because:

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Radius = 1
diameter = 2
7 0
3 years ago
Read 2 more answers
Can solids undergo convection
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5 0
3 years ago
I need help with this please
alexdok [17]

Answer:

polygons

Step-by-step explanation:

this is a hexagon so the sum of interior angles is 720. so add all of those angles and expressions and set it equal to 720. collect like terms and solve for x

once you have x, evaluate and get the exact angle measurements.

8 0
3 years ago
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
3 years ago
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