Answer: The volume of largest rectangular box is 4.5 units.
Step-by-step explanation:
Since we have given that
Volume = 
with subject to 
So, let 
So, Volume becomes,

Partially derivative wrt x and y we get that

By solving these two equations, we get that

So, 
So, Volume of largest rectangular box would be

Hence, the volume of largest rectangular box is 4.5 units.
Answer:
Step-by-step explanation:
Since this is a right angled triangle:
tan(∅) = opposite side/adjacent side
In this triangle:
tan(25°) = x/19
x = 8. 86 ≅ 8.9
Volume of a cube is Side to the third power ( S^3)
S = 3.2 meters
Volume = 3.2^3
Volume = 32.768 cubic meters (cm^3)
You may need to round the answer.. The problem doesn't say how many decimal places are needed.
Area of a triangle= 1/2 (ab) (sin C)
= 1/2 (9 x 11.5) (sin 63.4)
= 46.27