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prisoha [69]
3 years ago
9

Having a bit of trouble solving this problem

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0
X=7
25=DO
35=OG
THESE ARE THE ANSWERS
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Which algebraic expression is equivalent to the expression below?
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Using the formula a(b+c) = ab + ac, then 7(2x-6) = 14x - 42. The answer is D.
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Enter the difference between the rates of change for these two functions.
Alchen [17]

Answer:

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Step-by-step explanation:

Graph :

Choose any two points. (0 , 2) and (-1 , -2)

Rate of change = Change in y ÷ Change in x

                          = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=  \frac{-2 - 2}{-1 - 0}\\\\=  \frac{-4}{-1}\\\\= 4

Table:

Rate of change = \frac{-2-[-6]}{2-0}

                          =  \frac{-2+6}{2}\\\\=  \frac{4}{2}\\\\= 2

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2 years ago
The set of letters in the word "book"​
Helga [31]

Answer:

set of letters of word BOOK is

\{ B,O,K\}

mark brainliest please

6 0
3 years ago
Read 2 more answers
Divide x^6/(x^2+1) Please help quickly and thank you!
konstantin123 [22]
I think it's x^4.

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3 0
3 years ago
PLS PLS HELP, I DONT WANT TO FAIL!!
Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0
1 year ago
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