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2 years ago

14

The radius of a circle is 2 miles. What is the circle's area? r=2 mi Use 3.14 for .

1 answer:

umka2103 [35]2 years ago

5 0

Answer: A≈12.57mi²

Step-by-step explanation:

You might be interested in

Use the x-intercept method to find all real solutions of the equation.<br> x^3-8x^2+9x+18=0

meriva

Answer:

a. $x=-1,3,\:or\:6$

Step-by-step explanation:

The given equation is;

$x^3-8x^2+9x+18=0$

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator or software.

The corresponding function is

$f(x)=x^3-8x^2+9x+18$

The solution to $x^3-8x^2+9x+18=0$ is where the graph touches the x-axis.

We can see from the graph that; the x-intercepts are;

(-1,0),(3,0) and (6,0).

Therefore the real solutions are:

$x=-1,3,\:or\:6$

8 0

3 years ago

Read 2 more answers

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

2 years ago

What is the solution to<br> a>-16?

Anna11 [10]

Answer:

that is the solution

Step-by-step explanation:

it cannot be simplified

8 0

3 years ago

Which expression is equivalent to 33.63. 23 without exponents?

ehidna [41]

Yeah, what they said.

3 0

2 years ago

7,,,,,,,,,,,,,,,,,,,,please help

Goryan [66]

Answer:

1

Step-by-step explanation:

The given expression is

$\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}$

Recall and use

$a^m\times a^n=a^{m+n}$

$\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}$

$\frac{2^{-\frac{13}{2}}}{ 2^{-\frac{13}{2}}}$

Same bases are dividing, so we write one base and subtract the exponent.

$2^{-\frac{13}{2}+\frac{13}{2}}$

$2^0=1$

8 0

3 years ago