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MAVERICK [17]
2 years ago
11

Help with part b pls thank u

Mathematics
2 answers:
Vlad1618 [11]2 years ago
7 0

Answer:

  • See below

Step-by-step explanation:

  • speed = distance / time
  • time = distance / speed

a)

i)

<u>Time taken at the first part:</u>

  • 105 / x

ii)

<u>Time taken at the second part:</u>

  • (190 - 105) / (x + 12) =
  • 85/(x + 12)

b)

<u>If time is 3 hours and 15 minutes = 3 1/4 hours = 13/4 hours, the equation is:</u>

  • 105/x + 85/(x + 12) = 13/4
  • 4(x + 12)*105 + 4(85x) = 13x(x + 12)
  • 13x² - 604x - 5040 = 0

c)

<u>Solve the equation:</u>

  • 13x² - 604x - 5040 = 0
  • x = [604 ± √((-604)² + 4*13*5040) ]/26 =
  •      [604 ± √626896]/26 =
  •      [604 ± 791.77]/26
  • x = (604 + 791.77)/26 = 53.68 km/h (taking positive root only)

d)

  • 105/x = 105/53.68 h = 1.956 h = 1 h 0.956*60 min = 1 h 57 min (rounded)
  • 85/(53.68 + 12) = 85/65.68 = 1.294 h = 1 h 0.294*60 min = 1 h 18 min (rounded)
Flura [38]2 years ago
4 0

Answer:

see below

Step-by-step explanation:

Let t = time (in hours)

a) i)  <u>First 105 km of journey</u>

\mathsf{speed=\dfrac{distance}{time}}

\implies x=\dfrac{105}{t_1}

\implies t_1=\dfrac{105}{x}

ii) <u>Rest of journey</u>

distance = 190 - 105 = 85 km

speed = x+12 km/h

\mathsf{speed=\dfrac{distance}{time}}

\implies x+12=\dfrac{85}{t_2}

\implies t_2=\dfrac{85}{x+12}

b)  3 hours 15 minutes = 3.25 hours

\implies  total time = t_1+t_2=3.25

\implies \dfrac{105}{x}+\dfrac{85}{x+12} =3.25

\implies \dfrac{105(x+12)+85x}{x(x+12)} =3.25

\implies 105(x+12)+85x =3.25x(x+12)

\implies 105x+1260+85x =3.25x^2 +39x

\implies 3.25x^2-151x-1260=0

multiply by 4:

\implies 13x^2-604x-5040=0

c)

\textsf{quadratic formula} \ x=\dfrac{-b \pm\sqrt{b^2-4ac} }{2a}}

\implies  x=\dfrac{604 \pm\sqrt{(-604)^2-4(13)(-5040)} }{2(13)}}

\implies  x=\dfrac{604 \pm\sqrt{626896} }{26}}

\implies x = 53.68, x=-7.22

(to 2 decimal places)

d) time ≥ 0, therefore, x = 53.68 only

Substitute x = 53.68 into the expression for t_1 and solve for x:

\implies t_1=\dfrac{105}{53.68}=1.955912... \textsf{hours}=\textsf{1 hr 57 min}

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