Answer:
Kayla can put 9 stickers in each bag.
she can distribute it into bags of 9 stickers each of the same colour.
Step-by-step explanation:
Given;
yellow stickers = 36
red stickers = 27
blue stickers = 18
For her to distribute the stickers into bags so that each bag contains only one color of stickers and every bag has the same number of stickers without remainder.
We need to find the highest common factor of the number of the three colours.
36 = 4×9
27 = 3×9
18 = 2×9
We can see that they are all divisible by 9
Therefore, she can distribute it into bags of 9 stickers each
1) 8 + 4 = -5 + 7
12 = 2
FALSE
2) y = -11x + 4
(0, -7): -7 = -11(0) + 4 ⇒ -7 = 0 + 4 ⇒ -7 = 4 False
(-1, -7): -7 = -11(-1) + 4 ⇒ -7 = 11 + 4 ⇒ -7 = 15 False
(1, -7): -7 = -11(1) + 4 ⇒ -7 = -11 + 4 ⇒ -7 = -7 True
(2, 26): 26 = -11(2) + 4 ⇒ 26 = -22 + 4 ⇒ 26 = -18 False
Answer: C
3) Input Output
0 0
<u> 1 </u> 3
2 <u> 6 </u>
3 9
<u> 4 </u> <u> 12 </u>
5 15
6 <u> 18 </u>
Rule: input is being added by 1, output is 3 times x
4) c = 65h
5) 2x = -6

x = -3
6) 8j - 5 + j = 67
9j - 5 = 67 <em>added like terms (8j + j)</em>
<u> +5</u> <u>+5 </u>
9j = 72

j = 8
7) y = mx + b
<u> -b</u> <u> -b </u>
y - b = mx


Answer:
The test statistic needed to evaluate the claim is t = -1.08.
Step-by-step explanation:
The test statistic is:

In which X is the sample mean,
is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.
At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.
This means that 
Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.
This means that 
What is the test statistic needed to evaluate the claim?



The test statistic needed to evaluate the claim is t = -1.08.
Answer:
16
Step-by-step explanation:
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