Answer:
a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm
b.
sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.
than AT=BT
3x+6=42-x
3x+x=42-6
x=36/4=9
AT=3×9+6=27+6=33
c.
since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
EH=GH
5y+10=28-y
6y=28-10
y=18/6=3
Answer:
10^2+2×2b×10+2b^2 = 100+40b+2b^2
Answer:
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Step-by-step explanation:
ojblbuojbouvouvovuoub
Answer:
27y - 6
Step-by-step explanation:
3(9y - 2) Multiply 3 times each term in the parentheses
3 * 9y = 27y
3 * -2 = -6
