Answer:
C
Step-by-step explanation:
Firstly, we set up the null and alternative hypothesis as follows;
The null hypothesis is;
H0: μ ≥ 12
The alternative hypothesis is;
Ha : μ < 12
Next step is to calculate the test statistic z
Mathematically;
z = (x - μ )/ σ /√n
= (11.58 - 12) /1.93/√(80
Test statistic z = -1.92
Now we proceed to find the probability value that is equal to the value of the test statistic. We can find this by using the standard normal table or NORMSTD function on excel
P(z < -1.92) = 0.0274
P-value = 0.0274
alpha = 0.05
From the above, we can see that
P-value < alpha
And because of this, we are going to reject the null hypothesis and therefore accept the alternative.
We then conclude that there is sufficient evidence to conclude that "The average battery life (between charges) of this model of tablet is at least 12 hours."
Answer:
im sry i need hte points
Step-by-step explanation:
Solution :
Let 
and 
represents the proportions of the seeds which germinate among the seeds planted in the soil containing 
and 
mushroom compost by weight respectively.
To test the null hypothesis 
against the alternate hypothesis 
.
Let 
denotes the respective sample proportions and the 
represents the sample size respectively.
The test statistic can be written as :
which under 
follows the standard normal distribution.
We reject at 
level of significance, if the P-value 
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 
= 0.171335
Since the p-value > 0.05 and 
, so we fail to reject at level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the 
of the seeds that 
with the percent of the 
in the soil.
The other number could be 6. The GCF of 6 and 24 is 6, and 6 is less than 30.
