Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Solve for x. 3x2 + 13x = 10

Answer 1

$3x^2+13x=10\ \ \ |-10\\\\3x^2+13x-10=0\\\\3x^2+15x-2x-10=0\\\\3x(x+5)-2(x+5)=0\\\\(x+5)(3x-2)=0\iff x+5=0\ \vee\ 3x-2=0\\\\x+5=0\ \ \ \ |-5\\\boxed{x=-5}\\\\3x-2=0\ \ \ \ |+2\\3x=2\ \ \ \ |:3\\\boxed{x=\dfrac{2}{3}}\\\\Answer:\ x=-5\ or\ x=\dfrac{2}{3}$