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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Solve for x. 3x2 + 13x = 10

Mathematics

1 answer:

AlekseyPX3 years ago

6 0

$3x^2+13x=10\ \ \ |-10\\\\3x^2+13x-10=0\\\\3x^2+15x-2x-10=0\\\\3x(x+5)-2(x+5)=0\\\\(x+5)(3x-2)=0\iff x+5=0\ \vee\ 3x-2=0\\\\x+5=0\ \ \ \ |-5\\\boxed{x=-5}\\\\3x-2=0\ \ \ \ |+2\\3x=2\ \ \ \ |:3\\\boxed{x=\dfrac{2}{3}}\\\\Answer:\ x=-5\ or\ x=\dfrac{2}{3}$

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If a line segment is perpendicular to another line segment, it is the bisector of that line segment.

sp2606 [1]

False. Perpendicular lines run beside each other not through each other.

7 0

4 years ago

Find the distance between the points G(-5, 4) and H(2, 6).

vladimir2022 [97]

Answer:

The answer is

<h2> $\sqrt{53} \: \: or \: \: 7.28 \: \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

G(-5, 4) and H(2, 6)

The distance between them is

$|GH | = \sqrt{ ({ - 5 - 2})^{2} + ({4 - 6})^{2} } \\ = \sqrt{ ({ - 7})^{2} + ( { - 2})^{2} } \: \\ = \sqrt{49 + 4} \\ = \sqrt{53} \: \: \: \: \: \: \: \: \\ = 7.280109$

We have the final answer as

$\sqrt{53} \: \: or \: \: 7.28 \: \: \: \: units$

Hope this helps you

4 0

3 years ago

Find the amount in the bank after 7 years if interest is compounded quarterly?

qwelly [4]

Answer:

a) amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

Step-by-step explanation:

We are given:

Principal Amount P= 5000

Rate r= 4% = 0.04

time t = 7 years

The formula used is: $A=P(1+\frac{r}{n})^{nt}$

where A is future value, P is principal amount, r is rate, n is compounded value and t is time

a) Find the amount in the bank after 7 years if interest is compounded quarterly?

If interest is compounded quarterly then n = 4

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{4})^{4*7} \\A=5000(1+0.01)^{28}\\A=5000(1.01)^{28}\\A=5000(1.321)\\A=6,605$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) Find the amount in the bank after 7 years if interest is compounded monthly?

If interest is compounded quarterly then n = 12

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{12})^{12*7} \\A=5000(1+0.003)^{84}\\A=5000(1.003)^{84}\\A=5000(1.322)\\A=6,612.57$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

6 0

3 years ago

Solve (x + 2 < 5) ∩ (x - 7 > -6).

mihalych1998 [28]

Answer:

Step-by-step explanation:

x + 2 < 5 <em>subtract 2 from both sides</em>

x + 2 - 2 < 5 - 2

x < 3

x - 7 > -6 <em>add 7 to both sides</em>

x > 1

From x < 3 and x > 1 we have 1 < x < 3

7 0

4 years ago

Trọng lượng một sp là bnn pp chuẩn với trung bình là 20,5 và độ lệch chuẩn là 2. Lấy ngẫu nhiên 4 sp để kiểm tra thì với xs 0,95

Illusion [34]

You need to make this is all languages if you want help thank you . :)

8 0

3 years ago