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Inessa05 [86]
3 years ago
8

Steven brought a shirt and a pair of shoes for $95.50. If the shirt costs $12.30 more than the shoes, what was the price of the

shirt? Working Out plz?
Mathematics
1 answer:
storchak [24]3 years ago
7 0
53.95 dollars (yes that is correct)
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A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

5 0
3 years ago
Find the distance between the points (1, 5) and (1, -4).
Ganezh [65]

Answer:

9

Step-by-step explanation:

\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9

6 0
3 years ago
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I need some help on my math test!!, I get to retake it but I need help with some of it:
Greeley [361]

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = \frac{1}{2}, thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute (- 4, - 9) into the partial equation

- 9 = - 2 + c ⇒ c = - 9 + 2 = - 7

y = \frac{1}{2} x - 7 ← equation of line

7 0
3 years ago
What is the Y- Intercept <br><br> |A| (0,6)<br> |B| (3,0)<br> |C| (0,3)<br> |D| (6,0)
Elza [17]
The answer to your question is (0,3)
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3 years ago
Find the missing number (i.e. the coefficient in front of x) so that the equation has no solutions: □x + 4 = 4x + 15
Rina8888 [55]

Answer:

X=8

Step-by-step explanation:

4 0
3 years ago
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