Answer:
I was wondering if you could give me brainliest because I am almost to level ace! It would mean alot!
Step-by-step explanation:
Have a good day! :)
Answer:
30x -12
Step-by-step explanation:
the product rule is f(x)g'(x) + g(x)f'(x)
in this case f(x) = 3x-3 and g(x) = 5x+1. So we can just plug in we are going to find the derivative of each here.
f'(x) = 3 g'(x) = 5 Let me know if you don't know how I found the derivative of each.
Now we plug in.
f(x)g'(x) + g(x)f'(x)
(3x-3)5 + (5x+1)3
15x - 15 + 15x + 3
30x -12
You can further factor it but I'm gonna leave it like this.
You balance one of the unknowns in the equation then divide the coefficient of the unknown by itself
Answer:
1 mile
Step-by-step explanation:
0.5 hrs is 1/2 hrs
so 1/2 *2 + 1 mile
So firstly, the three terms share a GCF of x, so factor that out: 
Next, I'm going to be factoring by grouping. But first, what two terms have a product of 140x^2 and a sum of 33x? That would be 28x and 5x. Replace 33x with 5x + 28x: 
Now factor 20x^2 + 5x and 28x + 7 separately, make sure that they have the same quantity on the inside: ![x[5x(4x+1)+7(4x+1)]](https://tex.z-dn.net/?f=%20x%5B5x%284x%2B1%29%2B7%284x%2B1%29%5D%20)
<u>Now you can rewrite the expression as ![x[(5x+7)(4x+1)]](https://tex.z-dn.net/?f=%20x%5B%285x%2B7%29%284x%2B1%29%5D%20)
, which is your final answer.</u>
